Answer:
6s
Explanation:
Assume it is dropped from rest and the gravitational acceleration is 10
By the equation of motion under constant acceleration:

180 = (0)t+10(t^2)/2
t = 6 or -6 (rejected)
t = 6 s
Answer:
The crest to trough distance = 8 m
Explanation:
Given that,
The amplitude of a particular wave is 4.0 m.
We need to find the crest to trough distance.
We know that,
Amplitude = The distance from the base line to the crest or the the distance from the baseline to the trough.
It means,
Distance from crest to trough = 2(Amplitude)
= 2(4)
= 8 m
Hence, the crest to trough distance is equal to 8 m.
Answer:
Δ v = 125 m/s
Explanation:
given,
mass of space craft = 435 Kg
thrust = 0.09 N
time = 1 week
= 7 x 24 x 60 x 60 s
change in speed of craft = ?
Assuming no external force is exerted on the space craft
now,



a = 2.068 x 10⁻⁴ m/s²
using equation of motion
Δ v = a t
Δ v = 2.068 x 10⁻⁴ x 7 x 24 x 60 x 60
Δ v = 125 m/s
If it is diamagnetic then it magnetise opposite to magnetic field
if paramagnetic it weekly magnetise in direction of magnetic field
if ferromagnetic it strongly magnetise in direction of magnetic field