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3 years ago

The speed of a wave is 50 cm/s and its wavelenght is 10 cm What is its frequency

Physics

2 answers:

Dovator [93]3 years ago

5 0

10cm is 2.5cm wavelength is

Taya2010 [7]3 years ago

4 0

Answer:

5hz

Explanation:

the equation for frequency is velocity/wavelength

50 divided by 10 is 5

the frequency of the wave is 5hz

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Comic-strip hero superman meets an asteroid in outer space, and hurls it at 850 m/s, as fast as a bullet. the asteroid is three

Vesnalui [34]

Before the asteroid is threw, the total momentum is zero, since neither Superman nor the asteroid are moving.

Conservation of momentum commands the total momentum after the astronaut is threw must be zero too. This means that Superman's backward momentum afterward throwing the asteroid is equivalent to the asteroid forwards momentum, in size.

Momentum is mass times velocity. We know the mass of the asteroid is 1000M and its velocity is 850 m/s, so its momentum is
(1000M)(850 m/s) = 850,000M m/s.

So to get the answer: dividing by Superman's mass, M, gives his recoil velocity o 850,000 m/s.

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3 years ago

An autographed baseball rolls off of a 0.76 m high desk and strikes the floor 0.61 m away from the desk. how fast was it rolling

zmey [24]

d = distance = 0.76 m 
a = acceleration due to gravity = 9.81 m/s^2
u = initial velocity = 0 (as the ball rolls off the table the vertical velocity = 0
t = time = missing so we need to solve it

So we use the equation d = ut + 1/2 at², and ever since u is zero, ut is zero and the equation becomes to d = 1/2 at² and this reorders to t = sqrt (2d/a) = 0.39 seconds.

Since there are no forces performing in the horizontal direction, this means that there is no acceleration in the horizontal direction and consequently the horizontal velocity is persistent.

Velocity = distance/ time.

Horizontal velocity is therefore horizontal distance/time = 0.61 m/0.39s = 1.56 m/s.

8 0

4 years ago

The greatest speed with which an athlete can jump vertically is around 5 m/sec. Determine the speed at which Earth would move do

katrin2010 [14]

Answer:

Approximately $2.0 \times 10^{-23}\; \rm m \cdot s^{-1}$ if that athlete jumped up at $1.8\; \rm m \cdot s^{-1}$ . (Assuming that $g = 9.81\; \rm m\cdot s^{-1}$ .)

Explanation:

The momentum $p$ of an object is the product of its mass $m$ and its velocity $v$ . That is: $p = m \cdot v$ .

Before the jump, the speed of the athlete and the earth would be zero (relative to each other.) That is: $v(\text{athlete, before}) = 0$ and $v(\text{earth, before}) = 0$ . Therefore:

$\begin{aligned}& p(\text{athlete, before}) = 0\end{aligned}$ and $p(\text{earth, before}) = 0$ .

Assume that there is no force from outside of the earth (and the athlete) acting on the two. Momentum should be conserved at the instant that the athlete jumped up from the earth.

Before the jump, the sum of the momentum of the athlete and the earth was zero. Because momentum is conserved, the sum of the momentum of the two objects after the jump should also be zero. That is:

$\begin{aligned}& p(\text{athlete, after}) + p(\text{earth, after}) \\ & =p(\text{athlete, before}) + p(\text{earth, before}) \\ &= 0\end{aligned}$ .

Therefore:

$p(\text{athelete, after}) = - p(\text{earth, after})$ .

$\begin{aligned}& m(\text{athlete}) \cdot v(\text{athelete, after}) \\ &= - m(\text{earth}) \cdot v(\text{earth, after})\end{aligned}$ .

Rewrite this equation to find an expression for $v(\text{earth, after})$ , the speed of the earth after the jump:

$\begin{aligned} &v(\text{earth, after}) \\ &= -\frac{m(\text{athlete}) \cdot v(\text{athlete, after})}{m(\text{earth})} \end{aligned}$ .

The mass of the athlete needs to be calculated from the weight of this athlete. Assume that the gravitational field strength is $g = 9.81\; \rm N \cdot kg^{-1}$ .

$\begin{aligned}& m(\text{athlete}) = \frac{664\; \rm N}{9.81\; \rm N \cdot kg^{-1}} \approx 67.686\; \rm N\end{aligned}$ .

Calculate $v(\text{earth, after})$ using $m(\text{earth})$ and $v(\text{athlete, after})$ values from the question:

$\begin{aligned} &v(\text{earth, after}) \\ &= -\frac{m(\text{athlete}) \cdot v(\text{athlete, after})}{m(\text{earth})} \\ &\approx -2.0 \times 10^{-23}\; \rm m \cdot s^{-1}\end{aligned}$ .

The negative sign suggests that the earth would move downwards after the jump. The speed of the motion would be approximately $2.0 \times 10^{-23}\; \rm m \cdot s^{-1}$ .

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3 years ago

!!!! pleaseee helppp!!!!

aleksandrvk [35]

YES I WILL HELP YOU SO MUCH

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3 years ago

What is the relationship between chromosomes and a body's appearance? (A) Chromosomes make it possible for all bodies to exactly

Katen [24]

Answer: The correct option is B.

Chromosomes contain genes that tell the body how to grow and work.

Explanation:

This is because chromosomes contain alot of human genes which are found in the nucleus and every humans have 23 pairs of chromosomes. The sets of genes determines some of the body features, characteristics or traits. The genes in the body form the genotype and the genotype is expressed physically which is now the phenotype i.e traits expressed physically in the body which is an indication of body appearance.

7 0

3 years ago