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Ivahew [28]
3 years ago
10

I’ll hand out that gawk gawk hand twist vacuum seal combo 30000 to whoever answers this

Physics
2 answers:
Karolina [17]3 years ago
8 0
It’s attract
Now give that Gawk Gawk hand twist vacuum seal combo 30000 playa
Bumek [7]3 years ago
5 0

Answer:

Attract

Explanation:

What are the options?

Can you mark brainliest?

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A car is idling at a stoplight. When the light turns green, the car takes 12 seconds to accelerate to 18.7 m/s. What is the aver
Sonbull [250]

Answer:

1.6 m/s^2

Explanation:

3 0
4 years ago
Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be a
Helen [10]

Complete Question

Consider a system consisting of an ideal gas confined within a container, one wall of which is a movable piston. Energy can be added to the gas in the form of heat by applying a flame to the outside of the container. Conversely, energy can also be removed from the gas in the form of heat by immersing the container in ice water. Energy can be added to the system in the form of work by pushing the piston in, thereby compressing the gas. Conversely, if the gas pushes the piston out, thereby pushing some atmosphere aside, the internal energy of the gas is reduced by the amount of work done.

          pV=nRT

so the absolute temperature T is directly proportional to the product of the absolute pressure p and the volume V,Here n denotes the amount of gas moles,which is a constant because the gas is confined and R is the universal constant

What is the \triangle U as the system of ideal gas goes from point A to point B on the graph recall u is proportional to T

Answer:

\triangle T=0

\triangle V=0

The gas A and B have same internal energy

Explanation:

From the question we are told that

Pa=u atm\\Va=1m^3\\Pb=1 atm\\Vb=4m^3

Generally the equation of temperature is mathematically given as

Ta=\frac{Pv}{nR}

Ta=\frac{u*1}{nR}

And

Tb=\frac{PbVb}{nR}

Tb=\frac{u*1}{nR}

Generally the change in temperature \triangle T is mathematically given as

\triangle T=Tb-Ta=Tb=\frac{u*1}{nR}-\frac{u*1}{nR}

\triangle T=0

Generally the change in internal energy \triangle V

\triangle V=nC_v \triangle T\\

\triangle V=0

Therefore with

\triangle T=0

\triangle v=0

The gas A and B have same internal energy

6 0
3 years ago
If the ultimate shear strength of steel is taken to be 3.00 109 Pa, what force is required to punch through a steel plate 1.60 c
photoshop1234 [79]

Answer:

Explanation:

Given

Ultimate shear strength \tau =3\times 10^9\ Pa

thickness of steel Plate t=1.60\ cm

Cross-sectional A=1.20\times 10^2\ cm^2

suppose d is the diameter of cross-section

\frac{\pi }{4}d^2=1.20\times 10^2

d=12.359\ cm

Shear area of circular cross-section

A_s=\pi dt

A_s=\pi \times 12.359\times 1.6

A_s=62.13\ cm^2

Shear Force F_s=A_s\times \tau

F_s=62.13\times 10^2\times 3000

F_s=18.639\ MN  

6 0
3 years ago
An arrow is shot at an angle 38 ◦ with the horizontal. It has a velocity of 46 m/s. How high will the arrow go?
Klio2033 [76]

Answer:

40·919 m

Explanation:

Initial velocity of the arrow = 46 m/s

Angle at which it is thrown from horizontal = 38°

<h3>At the maximum height, the vertical component of velocity will be 0</h3>

Initial velocity in vertical direction = 46 × sin(38) = 28·32 m/s

From the formula

<h3>v² - u² = 2 × a × s</h3>

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

Considering the formula in vertical direction and taking upward direction as positive

v = 0

u = 28·32 m/s

a = - g = - 9·8 m/s²

Let s be the maximum height

- 28·32² = - 2 × 9.8 × s

⇒ s = 40·919 m

∴ The arrow will go 40·919 m high

8 0
3 years ago
If the force exerted by a man is halved and the distance is multiplied by four, by which factor does the work change ?
jeyben [28]

increase factor by 8 thousands

6 0
3 years ago
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