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Tom [10]
2 years ago
10

How does temperature influence the appearance of a star? Give an example in your response.

Physics
1 answer:
loris [4]2 years ago
5 0

The cooler the temp of the star the star would appear to glisten a red. if the star is warmer the star would be a light blue or blue. An example would be the tiny red dwarf stars. they only have 7% of the suns heat so they appear red.

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Power selection feature for resistors to become water modules 10 liters of water at 25°C to đến
Mila [183]

Answer:

P = 2439.5 W = 2.439 KW

Explanation:

First, we will find the mass of the water:

Mass = (Density)(Volume)

Mass = m = (1 kg/L)(10 L)

m = 10 kg

Now, we will find the energy required to heat the water between given temperature limits:

E = mCΔT

where,

E = energy = ?

C = specific heat capacity of water = 4182 J/kg.°C

ΔT = change in temperature = 95°C - 25°C = 70°C

Therefore,

E = (10 kg)(4182 J/kg.°C)(70°C)

E = 2.927 x 10⁶ J

Now, the power required will be:

Power = P = \frac{E}{t}

where,

t = time = (20 min)(60 s/1 min) = 1200 s

Therefore,

P = \frac{2.927\ x\ 10^6\ J}{1200\ s}

<u>P = 2439.5 W = 2.439 KW</u>

7 0
2 years ago
Discuss whether any work is being done by each of the following agents and, if so, whether the work is positive or negative: (a)
Aleks04 [339]

Answer:

a) As the chicken is still, the displacement is zero, which implies that the work is zero.

b) as the person is still there is no displacement therefore the work is zero

c) Lagraua applies a vertical force and the displacement is vertical, therefore the Work is positive

d) the force of gravity is directed downwards and the displacement is upwards, therefore the angle between it is 180º and the 180º fly is -1. Consequently the lock is negative

e) when the person meticulously feels the upward force and the displacement is downward, therefore the work is negative

Explanation:

Work is defined by the expression

        W = F. r

bold letters indicate vectors, we can write this expression as a module

        W= F r cos θ

where is at the angle between force and displacement.

Let's apply this expression to the different cases

a) As the chicken is still, the displacement is zero, which implies that the work is zero.

b) as the person is still there is no displacement therefore the work is zero

c) Lagraua applies a vertical force and the displacement is vertical, therefore the Work is positive

d) the force of gravity is directed downwards and the displacement is upwards, therefore the angle between it is 180º and the 180º fly is -1. Consequently the lock is negative

e) when the person meticulously feels the upward force and the displacement is downward, therefore the work is negative

7 0
3 years ago
Determine the magnitude of the electrostatic force on a 0.06000 C charged object when it is placed in an electric field of magni
joja [24]

Answer:

Explanation:

Use the following equation:

E=\frac{q}{F} and solve for F:

F=\frac{q}{E} and filling in:

F=\frac{.0600}{1500}

F = 4.0 × 10^{-4 N

3 0
2 years ago
If a man does 4500 J of work from a high rise building of 10 m, what is his mass?
GalinKa [24]

Explanation:

The potential energy (Ep) = 4500 J

Ep = m. g. h

=> m = Ep/(g.h)

m = 4500/(10×10)

= 4500/100

= 45

so, the mass = 45 kgs

4 0
2 years ago
Read 2 more answers
43 kg bear slides, from rest, 15 m down a lodgepole pine tree, moving with a speed of 5.5 m/s just before hitting the ground. (a
olga2289 [7]

Answer:

-6327.45 Joules

650.375 Joules

378.47166 N

Explanation:

h = Height the bear slides from = 15 m

m = Mass of bear = 43 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of bear = 5.5 m/s

f = Frictional force

Potential energy is given by

P=mgh\\\Rightarrow P=43\times -9.81\times 15\\\Rightarrow P=-6327.45\ J

Change that occurs in the gravitational potential energy of the bear-Earth system during the slide is -6327.45 Joules

Kinetic energy is given by

K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times 43\times 5.5^2\\\Rightarrow K=650.375\ J

Kinetic energy of the bear just before hitting the ground is 650.375 Joules

Change in total energy is given by

\Delta E=fh=-(\Delta K+\Delta P)\\\Rightarrow fh=-(650.375-6327.45)\\\Rightarrow fh=5677.075\\\Rightarrow f=\frac{5677.075}{h}\\\Rightarrow f=\frac{5677.075}{15}\\\Rightarrow f=378.47166\ N

The frictional force that acts on the sliding bear is 378.47166 N

5 0
3 years ago
Read 2 more answers
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