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Aleks [24]
3 years ago
8

Help me please i don't want to fail

Mathematics
1 answer:
slega [8]3 years ago
3 0
The last one
It is a step by step process that you have to do
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What is 3 1/3 divided by 1/3
saveliy_v [14]
Convert 3 1/3 into a improper fraction:
= 10/3

Then flip the other fraction around and multiply them together:
1/3 -> 3/1
(10*3)/(3*1) = 30/3 = (30/3)/(3/3) = 10/1 = 10

The answer is 10
4 0
4 years ago
Read 2 more answers
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
Yo wus up my people, my names Pablo Tablo, I'm your avg joe looking for a very specific shawty, like 5'2 and blonde or brunette,
DochEvi [55]

Answer:

I- ayo bud are you that desperate-? :3

Step-by-step explanation:

:3

6 0
3 years ago
Please help i don’t understand this
swat32

Similar polygons only differ by a scaling factor. In other words, two polygons are similar if one is the scaled version of the other.

In particular, this implies that the angles are preserved, and the correspondent sides are in proportion.

These two polygons are both rectangles, so the angles are preserved. We must check the sides, and we have to check if the smaller sides are in the same proportion as the bigger sides.

So, the two rectangles are similar if the following is true.

4\div 5 = 11\div 12

In any proportion, the product of the inner terms must be the same as the product of the outer terms:

4\cdot 12 = 5\cdot 11 \iff 48=55

This is clearly false, and thus the two rectangles are not similar.

5 0
3 years ago
A wireless phone company charges a monthly fee of $39.99 plus $0.49 per minute for usage that exceeds the included minutes. Writ
Marizza181 [45]

Answer:

$54.20

Step-by-step explanation:

minute=m

total monthly cost = p

39.99 + .49m = p

39.99 + .49(29) =p

39.99 + 14.21 =p

54.2 =p

3 0
4 years ago
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