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WINSTONCH [101]
3 years ago
6

suppose a block of lead of mass 0.4kg at temperature of 95°C is dropped in a 2 kg of water originally at 20°C in a container. wh

at is the final temperature if no heat is lost to the container and the environment. ( Specif heat of lead is 128J/Kg°C and and specific heat of water is4184J/Kg°C​
Physics
1 answer:
Kipish [7]3 years ago
8 0
Kg kg kg kg kg gram kg kg kg kg kg
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A 2.00-kg block of ice is moving on a frictionless horizontal surface. At t = 0 the block is moving to the right with a velocity
enyata [817]

Answer:

Explanation:

a )

We shall apply the concept of impulse .

Impulse = force x time = change in momentum

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b )

Impulse applied = - 7 x 4 = - 28 kg m/s ( negative as direction of force is opposite motion )

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- 22 = 2v

v = - 11 m /s

object will move with 11 m /s in opposite direction .

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What other uses does petroleum have besides being used for fuel and lubricants
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What two factors will most likely change the speed of a mechanical wave?
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If we double the frequency of a system undergoing simple harmonic motion, which of the following statements about that system ar
AnnyKZ [126]

Answer:

a. The angular frequency is doubled.

e. The period is reduced to one-half of what it was.

Explanation:

Angular frequency is given as;

ω = 2πf

\frac{\omega _1}{f_1} = \frac{\omega _2}{f_2}

when the frequency is doubled

\frac{\omega _1}{f_1} = \frac{\omega _2}{(2f_1)} \\\\\omega _1 = \frac{\omega _2}{2}\\\\\omega _2 = 2\omega _1

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Amplitude in simple harmonic motion is the maximum displacement.

Frequency is related to period in simple harmonic motion as given in the equation below;

f = \frac{1}{T} \\\\f_1T_1= f_2T_2\\\\T_2 = \frac{f_1T_1}{f_2}

when the frequency is doubled;

T_2 = \frac{f_1T_1}{2f_1} \\\\T_2 = \frac{T_1}{2}

Thus, the period will be reduced to one-half of what it was.

5 0
3 years ago
You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfo
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Answer:

Explanation:

To convert gram / centimeter³ to kg / m³

gram / centimeter³

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= 10⁻³ / 10⁻⁶ kg / m³

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So we shall have to multiply be 10³ with amount in gm / cm³ to convert it into kg/m³

2.33 gram / cm³

= 2.33 x 10³ kg / m³ .

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3 years ago
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