The area under a graph is given by the integral of that function, evaluated in the interval of interest:
![\displaystyle \int_{-3}^2 x^2+4\;dx = \left[\dfrac{x^3}{3}+4x\right]_{-3}^2 = \left[\dfrac{2^3}{3}+4\cdot 2\right]-\left[\dfrac{(-3)^3}{3}+4\cdot(-3)\right] = \left[\dfrac{8}{3}+8\right]-\left[-9-12\right] = \dfrac{32}{3}+21 = \dfrac{95}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_%7B-3%7D%5E2%20x%5E2%2B4%5C%3Bdx%20%3D%20%5Cleft%5B%5Cdfrac%7Bx%5E3%7D%7B3%7D%2B4x%5Cright%5D_%7B-3%7D%5E2%20%3D%20%5Cleft%5B%5Cdfrac%7B2%5E3%7D%7B3%7D%2B4%5Ccdot%202%5Cright%5D-%5Cleft%5B%5Cdfrac%7B%28-3%29%5E3%7D%7B3%7D%2B4%5Ccdot%28-3%29%5Cright%5D%20%3D%20%5Cleft%5B%5Cdfrac%7B8%7D%7B3%7D%2B8%5Cright%5D-%5Cleft%5B-9-12%5Cright%5D%20%3D%20%5Cdfrac%7B32%7D%7B3%7D%2B21%20%3D%20%5Cdfrac%7B95%7D%7B3%7D)
Answer:
0.5
Step-by-step explanation:
you just move the decimal three times over to the left
I'm pretty sure the original price would be $90.75 because 3/4 is .75, so all you have to do is add that to the $90
Given:
• Total number of cans collected = 150
,
• Percent of cans that were soda = 58%
Let's find the number of other cans he collected.
To find the number of other cans, since the percent of soda is 58%, let's find the pecent of other cans.
Percent of other cans = 100% - 58% = 42%
The percent of other cans collected was 42%.
Now, to find the number of other cans collected, let's find 42% of the total number of cans collected 150.
We have:

Therefore, the number of other cans collected is 63 cans.
ANSWER:
63 cans