Answer: Reducing agent in the given reaction is
.
Explanation:
A reducing agent is defined as an element which tends to lose electrons to other element leading to an increase in its oxidation number.
In the given reaction, oxidation state of sulfur in
is +2 and
has 0 oxidation state.
In
oxidation state of S is 2.5 and in
oxidation state of I is -1.
Since, an increase in oxidation state of S is occurring from +2 to +2.5. Hence, it is acting as a reducing agent.
Thus, we can conclude that reducing agent in the given reaction is
.
Remember that carbon has 4 electrons in its valence shell meanwhile bromine has 7
So i think the lewis structure would be :
Br
C Br Br
Br
Hope this helps
There is acetone, xylene, and toluene in spray paint
Answer:
The charge of an atom is the number of protons minus the number of electrons.