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2 years ago

10

50 points for 2 questions and brainliest! Please help!!!!

1 answer:

zhannawk [14.2K]2 years ago

7 0

<em><u>Answer:</u></em>

<em><u> a)</u></em>

<em><u /></em>

<em><u>Explanation:</u></em>

<em><u /></em>

<em><u>6HCl + 2Al ---> 2AlCl3 + 3H2</u></em>

<em><u /></em>

<em><u>6 mol 2 mol</u></em>

<em><u /></em>

<em><u>As we can see 6 mol HCl produce 2 mol AlCl3.</u></em>

<em><u /></em>

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Describe a way to separate a mixture of sand and salt .

worty [1.4K]

Put water in it and the salt will dissolve and the sand will stay at the bottom

7 0

3 years ago

Which of the following solutions is a good buffer system?A solution that is 0.10 M HCN and 0.10 M NaClA solution that is 0.10 M

patriot [66]

Answer:

A solution that is 0.10 M HCN and 0.10 M LiCN

Explanation:

A good buffer system contains a weak acid and its salt or a weak base and its salt.
In this case; A solution that is 0.10 M HCN and 0.10 M LiCN, would make a good buffer system.
HCN is a weak acid, while LiCN is a salt of the weak acid, that is, CN- conjugate of the acid.

8 0

2 years ago

Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu

pochemuha

Answer : The volume of $CO_2$ will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

$HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2$

First we have to calculate the mass of $HCO_3^-$ in tablet.

$\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g$

Now we have to calculate the moles of $HCO_3^-$ .

Molar mass of $HCO_3^-$ = 1 + 12 + 3(16) = 61 g/mole

$\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles$

Now we have to calculate the moles of $CO_2$ .

From the balanced chemical reaction, we conclude that

As, 1 mole of $HCO_3^-$ react to give 1 mole of $CO_2$

So, 0.0202 mole of $HCO_3^-$ react to give 0.0202 mole of $CO_2$

The moles of $CO_2$ = 0.0202 mole

Now we have to calculate the volume of $CO_2$ by using ideal gas equation.

$PV=nRT$

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = $37^oC=273+37=310K$

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

$(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)$

$V=0.51411L=514.11ml$

Therefore, the volume of $CO_2$ will be, 514.11 ml

6 0

2 years ago

Potassium chlorate (used in fireworks, flares, and safety matches) forms oxygen and potassium chloride when heated. KClO3(s) → K

Zina [86]

Answer:

10.3 g of oxygen are formed when 26.4 g of potassium chlorate is heated

Explanation:

This is the balanced equation:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

Ratio beteween the salt and oxygen is 2:3

Molar mass of KClO₃ = 122.55 g/m

Let's find out the moles of salt

Mass / Molar mass

26.4 g /122.55 g/m = 0.215 moles

So, this is the final rule of three:

If 2 moles of KClO₃ make 3 moles of oxygen

0.215 moles of KClO₃ make (0.215 .3) /2 = 0.323 moles of O₂ are produced

Molar mass O₂ = 32 g/m

Moles . molar mass = mass

0.323 m . 32g/m = 10.3 g

4 0

3 years ago

What are three ways heat is transfered

Gre4nikov [31]

Answer:

Conduction, Convection and Radiation

Explanation:

6 0

2 years ago

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