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3 years ago

What is the halogen in period 5?? it has six letters

1 answer:

8 0

Simple,

take a look at your periodic table, if you have it labeled look at the Halogen

Group, it includes: Flourine, Chlorine, Bromine, Iodine, and Astatine.

Now, a period on the periodic table is read from left to right, and goes

down the rows of the periodic table.

Go to Period 5, go all the way to the Halogens, what is there?

Iodine.

Thus, your answer.

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Using the equations

Anna [14]

Considering the Hess's Law, the enthalpy change for the reaction is 221.8 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: H₂ (g) + F₂ (g) → 2 HF (g) ∆H° = -79.2 kJ/mol

Equation 2: C (s) + 2 F₂ (g) → CF₄ (g) ∆H° = 141.3 kJ/mol

Equation 3: 2 C(s) + 2 H₂ (g) → C₂H₄ (g) ∆H° = -97.6 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

<h3 /><h3>FIRST STEP</h3>

First, to obtain the enthalpy of the desired chemical reaction you need one mole of C₂H₄ (g) on reactant side and it is present in first equation. Since this equation has one mole of C₂H₄ (g) on the product side, it is necessary to locate it on the reactant side (invert it).

When an equation is inverted, the sign of ΔH° also changes.

<h3>SECOND STEP</h3>

Now, you need 2 moles of CF₄ (g) on the product side. The second equation has 1 mole of CF₄ (g) on the product side, so it is necessary to multiply it by 2 to obtain 2 moles of CF₄ (g).

Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

<h3>THIRD STEP</h3>

Finally, you need 4 moles of HF (g) on the product side. The first equation has 2 moles of HF (g) on the product side, so it is necessary to multiply it by 2 to obtain 4 moles of the compound.

Since the equation is multiply by 2, the variation of enthalpy also is multiplied by 2.

<h3>SUMMARY</h3>

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 H₂ (g) + 2 F₂ (g) → 4 HF (g) ∆H° = -158.4 kJ/mol

Equation 2: 2 C (s) + 4 F₂ (g) → 2 CF₄ (g) ∆H° = 282.6 kJ/mol

Equation 3: C₂H₄ (g) → 2 C(s) + 2 H₂ (g) ∆H° = 97.6 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g) ΔH°= 221.8 kJ/mol

Finally, the enthalpy change for the reaction is 221.8 kJ/mol.

Learn more about molar enthalpy:

7 0

2 years ago

PLEASE ANSWER ASAP- In the solid state, how does Water compare to Neon and Argon? Why do you think they act differently?

alekssr [168]

Neon and Argon are known as the noble gases. This means that there inert and don’t typically react. The noble gases have full outer shells and therefore satisfy the octet rule. Hydrogen, on the other hand, must lose an electron to become stable. That is why it reacts.

3 0

3 years ago

What are three ways invasive species can be introduced into an environment?

Naily [24]

Answer:

Explanation:

6 0

2 years ago

Chlorine + sulfur dioxide + water = hydrochloric acid + sulfuric acid

scZoUnD [109]

The given example is a chemical reaction.

The contents (separated as reactants and products) :

$\begin{tabular}{c | l}Reactants & Products \\\cline{1-2}Chlorine & Sulfuric Acid \\Water & Hydrochloric Acid \\Sulfur Dioxide & \\\end{tabular}$

The written reaction is :

$\boxed {Cl + SO_{2} + H_{2}O \implies HCl + H_{2}SO{4}}$

<em>I hope it helped you solve the problem.</em>

<em>Good luck on your studies!</em>

7 0

2 years ago

Give an example where handpicking is used for separation. (1)

dimulka [17.4K]

Answer:

If you want to separate black grapes from the mixture of black and green grapes, then you will simply pick black grapes using your hands from the mixture. In this way you are actually using handpicking separation method.

Explanation:

5 0

2 years ago