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AveGali [126]
2 years ago
10

The ______ are new substances taht are created following a chemical reaction?

Chemistry
1 answer:
aleksandrvk [35]2 years ago
3 0
Answer: The product are the new substances that are created following a chemical reaction.
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A student is asked to determine the molarity of a strong base by titrating it with 0.250 M solution of H2SO4. The students is in
tamaranim1 [39]

Answer:

The molarity of the strong base is 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

Explanation:

<u>Step 1:</u> Data given

Molarity of H2SO4 = 0.250 M

The initial buret reading is 5.00 mL

The final reading is 30.00 mL

<u />

<u>Step 2:</u> Calculate volume of H2SO4 used

30.00 mL - 5.00 mL = 25.00 mL

<u>Step 3:</u> Calculate moles of H2SO4

0.250 M = 0.250 mol/L

Since there are 2 H+ ions per H2SO4

0.250 mol/L  * 2 = 0.500 mol/L

The number of moles H2SO4 = 0.500 mol/L * 0.025 L

Number of moles H2SO4 = 0.0125 mol

<u>Step 4</u>: Calculate moles of OH-

For 1 mol H2SO4, we need 1 mol of OH-

For 0.0125 mol of H2SO4, we have 0.0125 mol of OH-

<u>Step 5</u>: Calculate the molarity of the strong base

Molarity = moles / volume

Molarity OH- = 0.0125 mol / 0.02 L

Molarity OH - = 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

   

5 0
3 years ago
What does weight measure?
Maru [420]

Answer:

C Force of gravity acting on an object

Explanation:

Hope that helps

have A good day

can I i have brain pls

8 0
2 years ago
Read 2 more answers
A 8.65-L container holds a mixture of two gases at 11 °C. The partial pressures of gas A and gas B, respectively, are 0.205 atm
Vsevolod [243]

 The  total pressure  = 1.402 atm


<u><em>calculation</em></u>

Total  pressure = partial  pressure  of gas A + partial pressure of gas B +  partial pressure  of third gas

partial  pressure  of gas A= 0.205 atm

Partial pressure of gas B =0.658 atm


partial pressure for third gas is calculated using ideal  gas equation

that is PV=nRT   where,

p(pressure)=? atm

V(volume) = 8.65 L

n(moles)= 0.200 moles

R(gas constant)=0.0821 L.atm/mol.k

T(temperature) = 11°c into kelvin =11+273 =284 k

make  p the subject of the formula by  diving both side by V

p =nRT/v


p = [(0.200 moles x 0.0821 L.atm/mol.K x 284 K)/8.65L)] =0.539 atm



Total  pressure  is therefore = 0.205 atm +0.658 atm +0.539 atm

=1.402 atm

6 0
3 years ago
2 grams of hydrogen diffuses from containers in 10 minutes. How many grams of oxygen would diffuse through same container in sam
Leya [2.2K]

Answer:20

Explanation:make sure you thank me

4 0
2 years ago
Shawn wants to buy a pair of gloves online. She needs to
Ksivusya [100]
The answer would be millimeters
so answer choice d
5 0
3 years ago
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