Answer:
B
Step-by-step explanation:
I am assuming that the university has much more than 100 students so 100 people is just a small sample.
WANR: 22%
WWCN: 41%
WCLM: 24%
WKOD: 13%
However is B. WWCN.
Answer:
(1,1)
Step-by-step explanation:
we have
----> equation A
----> equation B
we know that
The solution of the system of equations is the intersection point both graphs
The intersection point both graphs is the point (1,1)
see the given graph
therefore
The solution is the point (1,1)
Remember that
if a ordered pair is a solution of a system of equations then the ordered pair must satisfy both equations of the system
<u><em>Verify</em></u>
Substitute the value of x=1 and y=1 in each equation and analyze the result
<em>Equation A</em>

---> is true
so
The ordered pair satisfy the equation A
<em>Equation B</em>
---> is true
so
The ordered pair satisfy the equation B
therefore
The ordered pair (1,1) is a solution of the system because satisfy both equations
Answer:
C
Step-by-step explanation:
Where, if at all possible,
A
,
B
, and
C
are integers, and A is non-negative, and, A, B, and C have no common factors other than 1
The picture is incomplete and the width is missing.
I am going to show you how to do it using any width.
The length shown is x + 4 and the width starts with - x.
Assume the width is - x + a.
Then the area of the rectangle with dimensions x + 4 and - x + a is calculated in this way:
1) given: (x + 4) (- x + a)
2) use distribuitive property: (x)(-x) + (x)(a) + (4)(-x) + (4)(a)
= - x^2 +ax -4x + 4a
3) Combine like terms: - x^2 + (a -4)x + 4a
If the polynomial missing were - x + 7, the answer would be:
- x^2 + (7 -4)x + 4(7) = - x^2 + 3x + 28
With this you are able to get the answer using the real values.