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Vsevolod [243]
3 years ago
12

Use the expressions that represent the length and width of the game board to write an equation that models the area of the figur

e. Let y represent the area, and write your answer in the form y=ax^2+bx+c, where a,b, and c are real numbers.

Mathematics
1 answer:
Ne4ueva [31]3 years ago
3 0
The picture is incomplete and the width is missing.

I am going to show you how to do it using any width.

The length shown is x + 4 and the width starts with - x.

Assume the width is - x + a.

Then the area of the rectangle with dimensions x + 4 and - x + a is calculated in this way:

1) given: (x + 4) (- x + a)

2) use distribuitive property: (x)(-x) + (x)(a) + (4)(-x) + (4)(a)

= - x^2 +ax -4x + 4a

3) Combine like terms: - x^2 + (a -4)x + 4a

If the polynomial missing were - x + 7, the answer would be:

- x^2 + (7 -4)x + 4(7) = - x^2 + 3x + 28

With this you are able to get the answer using the real values.
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The domain is the set of all values a function will accept as _____.
Marina86 [1]

Answer:

  ... inputs.

Step-by-step explanation:

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8 0
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A parabola has an x-intercept of -1, a y-intercept of -3, and a minimum of -4 at x = 1.
torisob [31]

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

In this problem we have

(h,k)=(1,-4)

substitute

y=a(x-1)^{2}-4

we have

An x-intercept of (-1,0)

substitute and solve for a

0=a(-1-1)^{2}-4

0=4a-4

4a=4

a=1

The equation is

y=(x-1)^{2}-4

<u><em>Verify the y-intercept</em></u>

For x=0

y=(0-1)^{2}-4

y=-3

The y-intercept is the point (0,-3) -----> is correct

using a graphing tool

see the attached figure

4 0
3 years ago
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