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Vsevolod [243]
2 years ago
12

Use the expressions that represent the length and width of the game board to write an equation that models the area of the figur

e. Let y represent the area, and write your answer in the form y=ax^2+bx+c, where a,b, and c are real numbers.

Mathematics
1 answer:
Ne4ueva [31]2 years ago
3 0
The picture is incomplete and the width is missing.

I am going to show you how to do it using any width.

The length shown is x + 4 and the width starts with - x.

Assume the width is - x + a.

Then the area of the rectangle with dimensions x + 4 and - x + a is calculated in this way:

1) given: (x + 4) (- x + a)

2) use distribuitive property: (x)(-x) + (x)(a) + (4)(-x) + (4)(a)

= - x^2 +ax -4x + 4a

3) Combine like terms: - x^2 + (a -4)x + 4a

If the polynomial missing were - x + 7, the answer would be:

- x^2 + (7 -4)x + 4(7) = - x^2 + 3x + 28

With this you are able to get the answer using the real values.
You might be interested in
Find the interior angle of a regular polygon which has 6 sides​
AveGali [126]

Answer:

120°.

Step-by-step explanation:

The sum of all interior angles in a polygon with n sides (n\in \mathbb{Z}, n \ge 3) is equal to (n - 2) \cdot 180^{\circ}. (Credit: Mathsisfun.)

The polygon here has 6 sides. n = 6. Its interior angles shall add up to (6 - 2) \times 180^{\circ} = 720^{\circ}.

Consider the properties of a regular polygon. (Credit: Mathsisfun.)

  • All sides in a regular polygon are equal in length.
  • All angles in a regular polygon are also equal.

There are six interior angles in a polygon with 6 sides. All six of them are equal. Thus, each of the six interior angle will be

\displaystyle \frac{1}{6}\times 720^{\circ} = 120^{\circ}.

5 0
2 years ago
How can you use similar triangles to solve problems?
mars1129 [50]

Answer:

you can use similar triangle to make known degrees in problems to make then easier to solve. With similar triangle, the angles are the same, but the scale is different. So by using this, one can solve both at the same time, and just just scale up the smaller one or scale down the larger, by the given/found scale.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Please need help i need help i need help
xeze [42]

Set each expression from the parentheses equal to 0 separately like so:

Equation 1: x - 4 = 0

Equation 2: -5x + 1 = 0

Now for each equation solve for x!

Equation 1:

x +(- 4 + 4) = 0 + 4

x = 4

Equation 2:

-5x +( 1-1) = 0 - 1

-5x/ -5 = -1 / -5

x = 1/5

Check:

(4 - 4)(-5*4 + 1)

(0) (-20 + 1)

(0) (-19)

0 = 0 -------------------------> correct!

(1/5 - 4)(-5 * 1/5 + 1)

(-19/5)(-1 + 1)

(-19/5)(0)

0 = 0 -------------------------> correct!

smaller x = 1/5

larger x = 4

Hope this helped!

8 0
2 years ago
Read 2 more answers
Six groups of students sell 162 balloons at the carnival .there are 3 students in each group. if each student sells the same num
Len [333]
It should be 54 because you half to divide 162 by 3


4 0
3 years ago
Can someone explain the process getting from:
spin [16.1K]
\rm 5=e^{3b}

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.

We'll take log of each side.
Log of what base tho?

Well, the base of our exponential is e,
so we'll take log base e of each side.

\rm log_e(5)=log_e(e^{3b})

We'll apply one of our log rules next:
\rm \log(x^y)=y\cdot\log(x)

This allows us to take the exponent out of the log,

\rm log_e(5)=(3b)log_e(e)

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,
\rm log_{10}(10)=1
\rm log_5(5)=1
\rm log_e(e)=1

So our equation simplifies to this,

\rm log_e(5)=(3b)\cdot1

As a final step, divide both sides by 3,

\rm \frac13log_e(5)=b

k, hope that helps!


6 0
3 years ago
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