Complete Question
If a logo has dimensions of 6 ft and 11ft, he needs a quart of paint for every 22 square ft. How many quarts will he need for the whole logo?
Answer:
3 quarts of paint
Step-by-step explanation:
The Logo is rectangular in shape, hence:
The area of a rectangle = Length × Width
The logo has dimensions of 6 ft and 11ft.
Area of the Logo = 6ft × 11ft = 66ft²
He needs a quart of paint for every 22 square ft
Hence:
22 ft² = 1 quart of paint
66ft² = x
Cross Multiply
22 ft² × x = 66 ft² × 1 quart
x = 66 ft² × 1 quart/22 ft²
x = 3 quarts of paint
Therefore, he will need 3 quarts of paint for the whole logo.
Answer:
4/3
Step-by-step explanation:
Using the formula of rise/run:
9-1 = 8
8-2 = 6
8/6 =4/3
Answer:
Step-by-step explanation:
Find the height of it with pythagoras
Root(100-36)=8
Volume = 1/3 pi r^2 h
1/3(36pi x 8)
=96pi
about 301.59ft^3
The answer is -13.
Solution:
= |-4b - 8| + |-1 - b^2| + 2b^3
= |-4(-2) - 8| + |-1 - -2^2| + 2(-2)^3
= |8-8| + |-1+4| + 2(-8)
= |0| + |3| + (-16)
= -13
