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3 years ago

8

Newton's Three Laws - Complete the sentences.

1 answer:

olasank [31]3 years ago

4 0

1. The answer is <span>An object won't move by itself, and once in motion, it won't stop unless some force acts upon it.
2. The rate of change of momentum is directly related to the force pressed upon it. In other words, when an object is pushed with more force, it will move faster and further away.
<span>3. To every action, there is equal and opposite reaction. </span></span>

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Please somebody answer I desperately need help!

padilas [110]

Preserved fossil<span> (like a fossil in amber, ice or tar.</span>

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4 years ago

Read 2 more answers

How many strings of length 10 over the alphabet (a, b, c, d] have at least one b somewhere in the string?

Lapatulllka [165]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is B

Explanation:

The number of alphabet is n= 4 (a , b , c , d )

Generally the total number of string of length 10 over the 4 alphabets is

$N = 4^{10}$

Gnerally the number of string of length 10 that does not include b is

$T = 3^{10}$

Generally the number of strings of length 10 over the 4 alphabets that have at least one alphabet b somewhere in the string is

$G = N - T$

=> $G = 4^{10} - 3^{10}$

8 0

3 years ago

Where do you weight more on top of Mt. Everest (Highest Mt. in the world) or at the beach

insens350 [35]

You weigh slightly more at the beach than on top of a mountain, because at the beach, you're closer to the center of the Earth.

8 0

3 years ago

A physics student walks 100 meters in 80 seconds. The student stops for 30 seconds, and then walks 200 meters farther in 90 seco

Elan Coil [88]

Answer:

B i think is the answer

Explanation:

i feel like it is B because if you put them together and the answer is 1.5 so it is B

8 0

3 years ago

The New Horizons spacecraft (mass 478 kg) was launched from earth in 2006 and flew past Pluto in 2015. What minimum amount of wo

Lena [83]

Answer: $2.98(10)^{10} J$

Explanation:

The work $W$ done by the gravitational force is given by:

$W=-\Delta U=-(-\frac{GMm}{d} - \frac{GMm}{D})$ (1)

Where:

$\Delta U$ is the variation in potential energy

$G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the Gravitational constant

$M=5.972(10)^{24} kg$ is the mass of the Earth

$m=478 kg$ is the mass of the spacecraft

$d=6371(10)^{3} m$ is the distance from the center of the Earth to its surface

$D=7.529(10)^{12} m$ is the distance between the Earth and Pluto

Rearranging (1):

$W=GMm(\frac{1}{d} + \frac{1}{D})$ (2)

$W=(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(5.972(10)^{24} kg)(478 kg)(\frac{1}{6371(10)^{3} m} + \frac{1}{7.529(10)^{12} m})$ (3)

Finally:

$W=2.98(10)^{10} J$

6 0

3 years ago