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photoshop1234 [79]
3 years ago
9

A baseball on a T-ball stand has no momentum until it is hit with a bat. When Tyler swings the bat, it has a momentum of 12 kg m

/s. After the bat hits the ball, the ball has a momentum of 8 kg m/s. What is the momentum of the bat AFTER it hits the ball
Physics
2 answers:
Troyanec [42]3 years ago
0 0
Positive direction : bat swing

total momentum before = after
12(bat) + 0(ball) = 8(ball) + bat-after

bat-after is positive then direction is the same
marysya [2.9K]3 years ago
0 0

Answer:

4 kg m/s

Explanation:

According to the Law of Conservation of Momentum, the total momentum must be the same before and after a collision. The total momentum before the bat hit the ball was 12 kg m/s. After the collision, the ball has a momentum of 8 kg m/s. Therefore, the bat must have a momentum of 4 kg m/s.

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Consider the vector field. f(x, y, z) = xy2z2i x2yz2j x2y2zk (a) find the curl of the vector field?
Marat540 [252]

Observe that the given vector field is a gradient field:

Let f(x,y,z)=\nabla g(x,y,z), so that

\dfrac{\partial g}{\partial x} = x y^2 z^2

\dfrac{\partial g}{\partial y} = x^2 y z^2

\dfrac{\partial g}{\partial z} = x^2 y^2 z

Integrating the first equation with respect to x, we get

g(x,y,z) = \dfrac12 x^2 y^2 z^2 + h(y,z)

Differentiating this with respect to y gives

\dfrac{\partial g}{\partial y} = x^2 y z^2 + \dfrac{\partial h}{\partial y} = x^2 y z^2 \\\\ \implies \dfrac{\partial h}{\partial y} = 0 \implies h(y,z) = i(z)

Now differentiating g with respect to z gives

\dfrac{\partial g}{\partial z} = x^2 y^2 z + \dfrac{di}{dz} = x^2 y^2 z \\\\ \implies \dfrac{di}{dz} = 0 \implies i(z) = C

Putting everything together, we find a scalar potential function whose gradient is f,

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5 0
1 year ago
The force F is expressed in terms of the mass “m” and acceleration “a” according to the
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Answer:

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3 years ago
Two vectors are given by a = 8.6i + 5.1 j and b = 931 + 9.5.
skelet666 [1.2K]

Answer:

<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong):</em>

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Explanation:

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c) <u>Asumming (a</u><u> </u><u>+ b)·b</u> <em>instead a+b·b</em> we have:

(a + b)\cdot b = [(8.6 + 9.3)i + (5.1 + 9.5)j]\cdot (9.3i + 9.5j) = (17.9i + 14.6j)\cdot (9.3i + 9.5j) = 305.17

d) The component of a along the direction of b is:

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I hope it helps you!                        

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