Answer:
735N
Explanation:
Weight is a measurement of force.
F = Force
m = mass
a = acceleration
F = m*a
F = 75kg*9.8m/s²
F = 735N
To solve this problem we will start by considering how to calculate the apparent weight. On the sphere this will then be given that the real weight is the sum of the apparent weight and the Buoyant Force. Therefore we will have to

Here
= True Weight
= Apparent Weight
= Buoyant Force
If we seek to find the apparent weight we will have to,


Remember that
V = Volume (Volume Sphere)
= Density (At this case water density)
g = Gravitational acceleration


Therefore the apparent weight will be 0.1526N
Answer is B
Hope this helped!
When the resultant force is not equal to zero termed an unbalanced force. By procedures 4 and 5 students observe an unbalanced upward force on Box 1. Hence option 1 is right for the problem.
<h3>What is an unbalanced force?</h3>
The forces operating on a body are known as unbalanced forces when the resulting force exerted on it is not equal to zero.
Unbalanced forces acting on the body, causing it to modify its state of motion. To further grasp the nature of imbalanced forces.
<h3 />
The following reasons by which we can understand the unbalanced force caused by the box.
Due to these two reasons, books will move up.
By adding another mass to box 2. The box becomes lighter. As the box becomes lighter the gravity force acting on the box will be less due to which the box easily can move up.
By removing the two masses from box 1. Due to which other become heavier other becomes heavier pulling it down causing box 1 one to go up.
Hence by procedures 4 and 5 students observe an unbalanced upward force on Box 1. Hence option 1 is right for the problem.
To learn more about the unbalanced force refer to the link;
brainly.com/question/227461
The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.
Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h
We have to find the magnitude of the angular momentum
Let,
ρ = Density of air = 1.29 kg/m^3
v = Speed of wind = 73.0 mi/h = 0.032 km/s
M = angular momentum of air
Let the volume of air be 1 m^3
Mass = Volume x ρ = 1 x 1.29 = 1.29 kg
Momentum = M = mass x velocity
Momentum = 1.29 x 0.0032
Momentum = 4.128 x 10^(-3) kg·m^2/s
Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s
Learn more about angular momentum here:
brainly.com/question/7538238
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