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Burka [1]
2 years ago
7

PLS ANSWER QUICKLY FIRST CORRECT ANSWER GETS BRAINLY

Mathematics
1 answer:
tangare [24]2 years ago
6 0
The correct answer is A=0 and B=1 trust me, its the correct answer. it’s the solution in integer form which the answer choices are in. Hope that helps!
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What is the sum of a 7-term geometric series if the first term is -6, the last term is -24,576, and the common ratio is 4?
Zanzabum
<h3><u>Answer:</u></h3>

Hence, the sum of a 7-term geometric series is:

-32766.

<h3><u>Step-by-step explanation:</u></h3>

We have to find the sum of a 7-term geometric series (i.e. n=7) if the first term(a) is -6, the last term is -24,576, and the common ratio(r) is 4.

We know that the sum of the 7-term geometric series is given as:

S_n=a\times (\dfrac{r^n-1}{r-1})

On putting the value of a,n and r in the given formula we have:

S_7=(-6)\times (\dfrac{4^7-1}{4-1})\\\\\\S_7=-32766

Hence, the sum of a 7-term geometric series is:

-32766.

3 0
3 years ago
Read 2 more answers
1.) What is the equation of the path of firework #1? Write your equation in general form.
valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in y=ax^2+bx+c

it's easier to find vertex form first then expand to get general form

vertex form is y=a(x-h)^2+k where the vertex is (h,k) and a is a constant


firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

h_1=a(t-10)^2+50

to find the value of a, subsitute another point

(0,0)

0=a(0-10)^2+50)

0=100a+50

a=\frac{-1}{2}

so the equation in vertex form is h_1=\frac{-1}{2}(t-10)^2+50

expand to get general form

h_1=\frac{-1}{2}(t^2-20t+100)+50

h_1=\frac{-1}{2}t^2+10t-50+50

h_1=\frac{-1}{2}t^2+10t





2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is h_2=a(t-10)^2+72

find a

use another point

(0,22)

22=a(0-10)^2+72

22=100a+72

-50=100a

a=\frac{-1}{2}

so the equation in vertex form is h_2=\frac{-1}{2}(t-10)^2+72




3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50


domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0
3 years ago
Each year the seventh graders who study life science participate in a special field trip to the city zoo in 2010 the school paid
juin [17]

Answer:

Yes, the price the school pays each year in entrance fees is proportional to the number of students entering the zoo

Step-by-step explanation:

Relationships between two variables is proportional if their ratios are equivalent.

In 2010, the school paid $1,260 for 84 students to enter the zoo.

Ratio of the price the school pays each year in entrance fees to the number of students entering the zoo = 1260:84=15:1

In 2011, the school paid $1,050 for 70 students to enter the zoo.

Ratio of the price the school pays each year in entrance fees to the number of students entering the zoo = 1050:70=15:1

In 2012, the school paid $1,395 for 93 students to enter the zoo.

Ratio of the price the school pays each year in entrance fees to the number of students entering the zoo = 1,395:93=15:1

As 1260:84=1260:84=1,395:93=15:1,

the price the school pays each year in entrance fees is proportional to the number of students entering the zoo.

3 0
3 years ago
What is –2c = –c − 4
crimeas [40]

Answer:

c=4

Step-by-step explanation:

–2c = –c − 4

add c to both sides

-1c=-4

divide both sides by -1

c=4

6 0
3 years ago
Read 2 more answers
In rhombus MOTH, angle HTM=(5x+6) degrees. If angle HMO=(12x-6)degrees, what is angle HMO?
forsale [732]

Answer:

m∠HMO=102°

Step-by-step explanation:

we know that

In a Rhombus the diagonals bisect the angles and opposite angles are equal

In this problem

Angles HMO and HTO are opposite angles

m∠HMO=m∠HTO

m∠HTM=(1/2)m∠HMO ----> because the diagonals bisect the angles and opposite angles are congruent

substitute the values

(5x+6)\°=(1/2)(12x-6)\°

solve for x

10x+12=12x-6\\12x-10x=12+6\\2x=18\\x=9

<em>Find the measure of angle HMO</em>

m∠HMO=(12x-6)°

substitute the value of x

m∠HMO=(12(9)-6)=102°

see the attached figure to better understand the problem

5 0
3 years ago
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