Answer:
Step-by-step explanation:
Let's reformat both equations so that 
is by itself on each side:
Since we isolated to one side in both equations, we know the right-hand sides must be equal:
Solving for 
will give us the x-coordinate of the point of intersection:
Plugging in this x-coordinate to either of the above equations will give us the y-coordinate of the point of intersection:
Therefore, the point of intersection is 
Distance sqrt of (x2-x1)/(y2-y1).
Distance = sqrt of 8/-7
Hope this helps!
Simplify the following:
-3 x^2 + 2 y^2 + 5 x y - 2 y + 5 x^2 - 3 y^2
Grouping like terms, -3 x^2 + 2 y^2 + 5 x y - 2 y + 5 x^2 - 3 y^2 = (2 y^2 - 3 y^2) + 5 x y - 2 y + (5 x^2 - 3 x^2):
(2 y^2 - 3 y^2) + 5 x y - 2 y + (5 x^2 - 3 x^2)
2 y^2 - 3 y^2 = -y^2:
-y^2 + 5 x y - 2 y + (5 x^2 - 3 x^2)
5 x^2 - 3 x^2 = 2 x^2:
Answer: -y^2 + 5 x y - 2 y + 2 x^2
Answer:
x=20[vertically opposite angle are equal]
Answer:
Where are the statements?
