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weeeeeb [17]
3 years ago
13

10.0 g of Mg are reacted with 95.0 g of I2. If 27.5 g of magnesium iodide are obtained, what is the percent yield

Chemistry
1 answer:
Tom [10]3 years ago
8 0

Answer:

% yield of reaction is 26.4

Explanation:

The reaction is:

Mg + I₂ →  MgI₂

Our reactants are magnessium and iodine. We determine the moles of each to find the limiting reactant:

10 g . 1mol / 24.3 g = 0.411 moles of Mg

95 g . 1mol / 253.8g = 0.374 moles of I₂

Ratio is 1:1. For 1 mol of Mg we need 1 mol of iodine

For 0.411 moles, we need the same amount, but we only have 0.374 moles of iodine, that's why the gas is the limiting reactant.

As ratio is 1:1 again, 0.374 moles of iodine can produce 0.374 moles of MgI₂

We determine the mas (theoretical yield): 0.374 mol . 278.1 g/mol = 104 g

To calculate the percent yield:

% yield = (yield produced /theoretical yield) . 100

% yield = (27.5 g/ 104g) . 100 = 26.4

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Answer:

Why are redox reactions used in batteries? The attraction between charged ions releases energy. The movement of electrons creates an electric current. The reactions are extremely exothermic, producing an electric current.

Explanation:

Why are redox reactions used in batteries?

The attraction between charged ions releases energy.

The movement of electrons creates an electric current.

The reactions are extremely exothermic, producing an electric current.

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5 0
3 years ago
When mixed together, baking soda and vinegar undergo a chemical reaction. Carbon dioxide, water, and
Valentin [98]

Answer: baking soda + vinegar →  carbon dioxide + water + sodium acetate

8 0
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A 3.90L sample of gas at STP is cooled to -55oC at 808mmHg. What is the new volume?
notsponge [240]

Answer:

3.72L

Explanation:

Given parameters:

Initial volume V₁ = 3.9L

Condition  = STP

Final temperature T₂ = -550°C

Final pressure P₂  = 880mmHg

Unknown:

Final volume V₂  = ?

Solution.

At standard temperature and pressure(STP), the:

           Pressure  = 1atm   = 760mmHg

            Temperature  = 273K

Therefore, P₁  = 760mmHg

                  T₁  = 273K

The general gas law, is best to solve this problem. It is mathematically given as:

           \frac{P_{1} V_{1} }{T_{1} }   = \frac{P_{2} V_{2} }{T_{2} }

Let us take the units to the appropriate one;

      -550°C  = 273 + (-550) = -277K

Input the variables;

             \frac{760 x 3.9}{273}  = \frac{808 x V_{2} }{-277}

        V₂  = 3.72L

           

5 0
3 years ago
Friction factor for fluid flow in pipe does not depend upon the A. pipe length. B. pipe roughness. C. fluid density & viscos
Feliz [49]

Answer:

C. fluid density & viscosity

Explanation:

In 1850, Darcy-Weisbach experimentally deduced an equation to calculate shear losses ("friction"), in a tube with permanent flow and constant diameter:

hf = (f x L x V^2) / (D x 2g)

where:

hf: shear losses

f:  shear loss factor (pipe roughness)

g: gravity acceleration

D: tube diameter

L: tube length  

V: fluid average speed in the tube

To calculate the loss factor “f” in the Poiseuille laminar region, he proposed in 1846 the following equation:

f = 64 / Re

Where:

Re: Reynolds number

The influence of the parameters on f is quantitatively different according to the characteristics of the current.

In any straight pipeline that transports a liquid at a certain temperature, there is a critical speed below which the regimen is laminar. This critical value that marks the transition between the two regimes, laminar and turbulent, corresponds to a Re = 2300, although in practice, between 2000 and 4000 the situation is quite inaccurate. Thus:

Re <2000: laminar regimen

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8 0
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A chef finds a sealed container consisting of an ingredient that goes into his restaurant's secret sauce. The ingredient's molec
LenaWriter [7]

Answer:

faster, and the ingredient will be a liquid.

Explanation:

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