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Nadya [2.5K]
3 years ago
13

Given that the speed of light is 2.998 x 108 m/s, what is the frequency of a wave that has a wavelength of 3.55 x 10-8 meters?

Chemistry
1 answer:
sweet [91]3 years ago
4 0
Its very easy, all we need is the following formula

c= λ x ν

c= speed of light
λ= wavelength
ν= frequency

we can rearrange the formula to solve for the unknown asked.

ν= c/λ

v= (2.998 x 10^8)/ (3.55 x 10^-8)= 8.45 x 10^15

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Use MO diagrams to place B2+, B2, and B2- in order of (a) decreasing bond energy; (b) decreasing bond length.
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We use the MO diagram for a homonuclear diatomic species (since C and N are neighbours, we treat them as the "same").

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Adding one more to give CN- would give the bond order 6/2 = 3. (If we added more electrons, each one would lower the bond order.)

Given a series of molecules with identical skeletal structures, the one with the highest bond order has the highest bond energy:

CN+ < CN < CN-

Lewis structures will verify that CN- has a triple bond, but they do not work particularly well for CN+ and CN.

learn more about bond orders at

brainly.com/question/9713842

#SPJ1

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