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Brut [27]
3 years ago
12

Students are studying the effects of beach pollution by counting populations of seagulls at two different beach locations. One l

ocation is a beach near a large industrial marina where boats are serviced; the second location is an isolated beach surrounded by a state park. The students plan to count all the visible seagulls at the beaches at specific times of day. They will repeat the bird count for 10 days and then analyze the data.
What is the outcome variable (dependent variable) in this study?
Chemistry
1 answer:
WARRIOR [948]3 years ago
6 0
The weather/wind direction
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Write a net ionic equation for the reaction between mno4- and fe2+ in acid solution
dedylja [7]
Answer : The complete net ionic reaction between MnO _{4}  ^{-} and Fe ^{2+} in an acid solution, can be written as :-

MnO _{4}  ^{-}  + 5Fe ^{2+} + 8 H ^{+} ----\ \textgreater \  Mn ^{2+} + 5 Fe^{3+} + 4 H _{2}O.
6 0
3 years ago
Help me please!!!!!!!!?????
kirill [66]

Answer:

i believe its A or D

Explanation:

sorry is its wrong

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4 0
3 years ago
1. The pressure of a gas is 100.0 kPa and its volume is 500.0 ml. If the volume increases to 1,000.0 ml, what is the new pressur
marta [7]

Answer:

1) The new pressure of the gas is 500 kilopascals.

2) The final volume is 1.44 liters.

3) Volume will decrease by approximately 67 %.

4) The Boyle's Laws deals with pressures and volumes.

Explanation:

1) From the Equation of State for Ideal Gases we construct the following relationship:

\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}} (1)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kPa.

V_{1}, V_{2} - Initial and final pressure, measured in mililiters.

If we know that P_{1} = 100\,kPa, V_{1} = 500\,mL and V_{2} = 1000\,mL, then the new pressure of the gas is:

P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)

P_{2} = 500\,kPa

The new pressure of the gas is 500 kilopascals.

2) Let suppose that gas experiments an isothermal process. From the Equation of State for Ideal Gases we construct the following relationship:

\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}} (1)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kPa.

V_{1}, V_{2} - Initial and final pressure, measured in mililiters.

If we know that V_{1} = 3.60\,L, P_{1} = 10\,kPa and P_{2} = 25\,kPa then the new volume of the gas is:

V_{2} = V_{1}\cdot \left(\frac{P_{1}}{P_{2}} \right)

V_{2} = 1.44\,L

The final volume is 1.44 liters.

3) From the Equation of State for Ideal Gases we construct the following relationship:

\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}} (1)

Where:

P_{1}, P_{2} - Initial and final pressure, measured in kPa.

V_{1}, V_{2} - Initial and final pressure, measured in mililiters.

If we know that \frac{P_{2}}{P_{1}} = 3, then the volume ratio is:

\frac{V_{1}}{V_{2}} = 3

\frac{V_{2}}{V_{1}} = \frac{1}{3}

Volume will decrease by approximately 67 %.

4) The Boyle's Laws deals with pressures and volumes.

8 0
2 years ago
Boiling and melting points exploration<br>​
juin [17]

Answer:

Boiling- 212° F melting- 32°F

Explanation:

6 0
3 years ago
ICI(g) + Cl₂(g) → ICl3(s). The AG(f) of ICI(g) is -5.5 kJ/mol and the
DENIUS [597]

Answer:

KJ8RT898TGHO7-6734354546746R476

Explanation:

3 0
2 years ago
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