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3 years ago

If you have 100 grams of H2, how many moles of H2 is that?

Chemistry

2 answers:

hram777 [196]3 years ago

8 0

the 2 next the H indicates that there is two H is one molecule
49.6

kolezko [41]3 years ago

5 0

So you take 100 grams/1 times by 1moleH2/2.0158grams H2. The 2.0158 is the molar mass of Hydrogen times by 2 because of the H2, simplified to 100/2.0158= # of moles, So 50 wold be the answer.

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Consider the following reaction:

iren [92.7K]

Answer:

A. ΔG° = 132.5 kJ

B. ΔG° = 13.69 kJ

C. ΔG° = -58.59 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

We can calculate the standard enthalpy of the reaction (ΔH°) using the following expression.

ΔH° = ∑np . ΔH°f(p) - ∑nr . ΔH°f(r)

where,

n: moles

ΔH°f: standard enthalpy of formation

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g)) - 1 mol × ΔH°f(CaCO₃(s))

ΔH° = 1 mol × (-635.1 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1206.9 kJ/mol)

ΔH° = 178.3 kJ

We can calculate the standard entropy of the reaction (ΔS°) using the following expression.

ΔS° = ∑np . S°p - ∑nr . S°r

where,

S: standard entropy

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g)) - 1 mol × S°(CaCO₃(s))

ΔS° = 1 mol × (39.75 J/K.mol) + 1 mol × (213.74 J/K.mol) - 1 mol × (92.9 J/K.mol)

ΔS° = 160.6 J/K. = 0.1606 kJ/K.

We can calculate the standard Gibbs free energy of the reaction (ΔG°) using the following expression.

ΔG° = ΔH° - T.ΔS°

where,

T: absolute temperature

ΔG° = ΔH° - T.ΔS°

ΔG° = 178.3 kJ - 285K × 0.1606 kJ/K = 132.5 kJ

ΔG° = ΔH° - T.ΔS°

ΔG° = 178.3 kJ - 1025K × 0.1606 kJ/K = 13.69 kJ

ΔG° = ΔH° - T.ΔS°

ΔG° = 178.3 kJ - 1475K × 0.1606 kJ/K = -58.59 kJ

5 0

3 years ago

What is a cylinder? Give an example of an object that's a cylinder.

amid [387]

By definition a cylinder is a solid geometric figure with straight parallel sides and a circular or oval cross-section. A good example of a cylinder would be a soda can.

8 0

3 years ago

Read 2 more answers

1.- Ilumina de amarillo los verbos en pretérito y de verde los verbos en copretérito.

ivanzaharov [21]

Answer:

Pretérito (Pretérito perfecto):

estiró, sudó, peleó, compartí

Copretérito (Pretérito imperfecto):

saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian

Explanation:

Los verbos en pretérito, también llamado pretérito perfecto, son los siguientes:

estiró, sudó, peleó, compartí

Como se aprecia, los verbos conjugados en pretérito perfecto terminan la última sílaba en vocal con acento, es decir, -á, -é, -í u -ó.

Los verbos en copretérito, también llamado pretérito imperfecto, son los siguientes:

saludaba, pedias, leia, compraba, barrias, cargaba, estrenabas, escribian

Como se aprecia, los verbos conjugados en pretérito imperfecto terminan la última sílaba en -ía, ías, -ían, -aba, -abas o -aban.

3 0

2 years ago

An unknown substance has the following properties:

Anastasy [175]

Answer:

Homogenous mixture

Explanation:

Homogenous mixtures like ice cream appear to be uniform, and you cannot see their individual components.

6 0

3 years ago

Read 2 more answers

In preparation of aspirin why is water added

mafiozo [28]

The formation of aspirin will proceed faster if acetic anhydride is used in place of acetic acid.

However, acetic anhydride will hydrolyze in the presence of water to form acetic acid, slowing down the reaction.

8 0

3 years ago