Answer
Add the expressions.
1400
Step-by-step explanation:
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Answer:
The average rate of change of the function
over the interval
is -1
Step-by-step explanation:
We are given the function
over the interval ![-11 \leq x\leq -1](https://tex.z-dn.net/?f=-11%20%5Cleq%20x%5Cleq%20-1)
We need to find average rate of change.
The formula used to find average rate of change is : ![Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}](https://tex.z-dn.net/?f=Average%20%5C%20rate%20%5C%20of%20%5C%20change%3D%5Cfrac%7Bg%28b%29-g%28a%29%7D%7Bb-a%7D)
We have b=-1 and a=-11
Finding g(b) = g(-1)
![g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9](https://tex.z-dn.net/?f=g%28x%29%3Dx%5E2%2B10x%2B18%5C%5CPutting%20%5C%20x%3D-1%5C%5Cg%28-1%29%3D%28-1%29%5E2%2B10%28-1%29%2B18%5C%5Cg%28-1%29%3D1-10%2B18%5C%5Cg%28-1%29%3D9)
Finding g(a) = g(-11)
![g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29](https://tex.z-dn.net/?f=g%28x%29%3Dx%5E2%2B10x%2B18%5C%5CPutting%20%5C%20x%3D-11%5C%5Cg%28-11%29%3D%28-11%29%5E2%2B10%28-11%29%2B18%5C%5Cg%28-1%29%3D121-110%2B18%5C%5Cg%28-1%29%3D29)
Finding average rate of change
![Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1](https://tex.z-dn.net/?f=Average%20%5C%20rate%20%5C%20of%20%5C%20change%3D%5Cfrac%7Bg%28b%29-g%28a%29%7D%7Bb-a%7D%5C%5CAverage%20%5C%20rate%20%5C%20of%20%5C%20change%3D%5Cfrac%7B9-29%7D%7B-1-%28-11%29%7D%5C%5CAverage%20%5C%20rate%20%5C%20of%20%5C%20change%3D%5Cfrac%7B-10%7D%7B-1%2B11%7D%5C%5CAverage%20%5C%20rate%20%5C%20of%20%5C%20change%3D%5Cfrac%7B-10%7D%7B10%7D%5C%5CAverage%20%5C%20rate%20%5C%20of%20%5C%20change%3D-1)
So, the average rate of change of the function
over the interval
is -1
9/10 * 5 = 45/10 metres = 4 5/10 metres = 4 1/2 metres
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Answer:
Step-by-step explanation:
So first you do y=z and1+2=3 so 6=y=-0 is your answer :)