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3 years ago

Express 50,000 m/s2 in scientific notation. 5.0 x 103m/s2 0.5 x 105m/s2 5.0 x 104m/s2

Physics

2 answers:

Tresset [83]3 years ago

8 0

Answer would be 5.0x104m/s2

Vanyuwa [196]3 years ago

4 0

Answer:

5 x 104 m/s2

Explanation:

Remember to write a number in scientific notation you need to follow some steps.

1.- Write the number as a whole number, in this case 5

2.- the tenth will count the position of the decimal that moves until reach the number, in this case the decimal point moves 4 positions.

3.- If the number is bigger to 1, so the exponent will be positive, as in this case.

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2 years ago

Air as an ideal gas enters a diffuser operating at steady state at 5 bar, 280 K with a velocity of 510 m/s. The exit velocity is

Nataly [62]

Answer:

Explanation:

Calculating the exit temperature for K = 1.4

The value of $c_p$ is determined via the expression:

$c_p = \frac{KR}{K_1}$

where ;

R = universal gas constant = $\frac{8.314 \ J}{28.97 \ kg.K}$

k = constant = 1.4

$c_p = \frac{1.4(\frac{8.314}{28.97} )}{1.4 -1}$

$c_p= 1.004 \ kJ/kg.K$

The derived expression from mass and energy rate balances reduce for the isothermal process of ideal gas is :

$0=(h_1-h_2)+\frac{(v_1^2-v_2^2)}{2}$ ------ equation(1)

we can rewrite the above equation as :

$0 = c_p(T_1-T_2)+ \frac{(v_1^2-v_2^2)}{2}$

$T_2 =T_1+ \frac{(v_1^2-v_2^2)}{2 c_p}$

where:

$T_1 = 280 K \\ \\ v_1 = 510 m/s \\ \\ v_2 = 120 m/s \\ \\c_p = 1.0004 \ kJ/kg.K$

$T_2= 280+\frac{((510)^2-(120)^2)}{2(1.004)} *\frac{1}{10^3}$

$T_2 = 402.36 \ K$

Thus, the exit temperature = 402.36 K

The exit pressure is determined by using the relation: $\frac{T_2}{T_1} = (\frac{P_2}{P_1})^\frac{k}{k-1}$

$P_2=P_1(\frac{T_2}{T_1})^\frac{k}{k-1}$

$P_2 = 5 (\frac{402.36}{280} )^\frac{1.4}{1.4-1}$

$P_2 = 17.79 \ bar$

Therefore, the exit pressure is 17.79 bar

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2 years ago

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Leona [35]

The correct match of each item to the clean water regulation it describes is as follows:

Regulates pollutants discharged into surface waters: Clean water act
Covers both surface and ground waters: Safe drinking water act
Authorizes the EPA to establish minimum standards for tap water: Safe drinking water act
Funds sewage treatment plants: Clean water act

<h3>What are the functions of clean water regulation?</h3>

Clean Water Act (CWA) is a regulatory body that establishes the basic structure for the regulation of pollutants discharge and maintenance of quality standards of the surface waters.

On the other hand, the Safe Drinking Water Act was founded to oversee the protection of the quality drinking water. The regulatory body is primarily concerned with potable water all waters, whether from above ground or underground sources.

Therefore, the correct match of each item to the clean water regulation it describes is as follows:

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2 years ago

How was the speed of light determined

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2 years ago

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When Bella pushes a box with a mass of 5.25 kilograms with a force of 15.75 newtons, it accelerates at a rate of 2.5 meters/seco

Mariana [72]

Sure !

Start with Newton's second law of motion:

   Net Force = (mass) x (acceleration) .

This formula is so useful, and so easy, that you really
should memorize it.

Now, watch:

The mass of the box is 5.25 kilograms, and the box is
accelerating at the rate of 2.5 m/s² .
What's the net force on the box ?

Net Force = (mass) x (acceleration)

         = (5.25 kilograms) x (2.5 m/s²)

   Net force = 13.125 newtons .

But hold up, hee haw, whoa ! Wait a second !
Bella is pushing with a force of 15.75 newtons, but the box
is accelerating as if the force on it is only 13.125 newtons.
What happened to the rest of Bella's force ? ?

==> Friction is pushing the box in the opposite direction,
and cancelling some of Bella's force.

How much ?

(Bella's 15.75 newtons) minus (13.125 that the box feels)

   = 2.625 newtons backwards, applied by friction.

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3 years ago

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