The capacitive reactance of the capacitor is about 1740 Ω
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<h3>Further explanation</h3>
Let's recall Capacitive Reactance and Impedance formula as follows:

<em>where:</em>
<em>Xc = capacitive reactance ( Ohm )</em>
<em>ω = angular frequency ( rad/s )</em>
<em>C = capacitance ( F )</em>
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
<em>where:</em>
<em>Xc = capacitive reactance ( Ohm )</em>
<em>XL = inductive reactance ( Ohm )</em>
<em>R = resistance ( Ohm )</em>
<em>Z = impedance ( Ohm )</em>
Let us now tackle the problem!
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<u>Given:</u>
resistance = R = 250 Ω
capacitance = C = 4.80 μF = 4.80 × 10⁻⁶ F
angular frequency = ω = 120 rad/s
maximum voltage across the capacitor = Vc_max = 7.60 V
<u>Asked:</u>
capacitive reactance of the capacitor = Xc = ?
<u>Solution:</u>



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<h3>
Conclusion :</h3>
The capacitive reactance of the capacitor is about 1740 Ω
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<h3>Learn more</h3>
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<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Alternating Current