1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexandr1967 [171]
4 years ago
13

A 250 - ω resistor is connected in series with a 4.80 - μf capacitor. the voltage across the capacitor is vc=(7.60v)⋅sin[(120rad

/s) t ]. part a determine the capacitive reactance of the capacitor.

Physics
2 answers:
nata0808 [166]4 years ago
8 0

The capacitive reactance of the capacitor is about 1740 Ω

\texttt{ }

<h3>Further explanation</h3>

Let's recall Capacitive Reactance and Impedance formula as follows:

\boxed{ X_c = \frac{1}{ \omega C } }

<em>where:</em>

<em>Xc = capacitive reactance ( Ohm )</em>

<em>ω = angular frequency ( rad/s )</em>

<em>C = capacitance ( F )</em>

\texttt{ }

\boxed{ Z^2 = R^2 + (X_L - X_c)^2}

<em>where:</em>

<em>Xc = capacitive reactance ( Ohm )</em>

<em>XL = inductive reactance ( Ohm )</em>

<em>R = resistance ( Ohm )</em>

<em>Z = impedance ( Ohm )</em>

Let us now tackle the problem!

\texttt{ }

<u>Given:</u>

resistance = R = 250 Ω

capacitance = C = 4.80 μF = 4.80 × 10⁻⁶ F

angular frequency = ω = 120 rad/s

maximum voltage across the capacitor = Vc_max = 7.60 V

<u>Asked:</u>

capacitive reactance of the capacitor = Xc = ?

<u>Solution:</u>

X_c = \frac{1}{ \omega C }

X_c = \frac{1}{ 120 \times 4.80 \times 10^{-6} }

\boxed {X_c \approx 1740\ \Omega}

\texttt{ }

<h3>Conclusion :</h3>

The capacitive reactance of the capacitor is about 1740 Ω

\texttt{ }

<h3>Learn more</h3>
  • The three resistors : brainly.com/question/9503202
  • A series circuit : brainly.com/question/1518810
  • Compare and contrast a series and parallel circuit : brainly.com/question/539204

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Alternating Current

galben [10]4 years ago
6 0
<span>553 ohms The Capacitive reactance of a capacitor is dependent upon the frequency. The lower the frequency, the higher the reactance, the higher the frequency, the lower the reactance. The equation is Xc = 1/(2*pi*f*C) where Xc = Reactance in ohms pi = 3.1415926535..... f = frequency in hertz. C = capacitance in farads. I'm assuming that the voltage and resistor mentioned in the question are for later parts that are not mentioned in this question. Reason is that they have no effect on the reactance, but would have an effect if a question about current draw is made in a later part. With that said, let's calculate the reactance. The 120 rad/s frequency is better known as 60 Hz. Substitute known values into the formula. Xc = 1/(2*pi* 60 * 0.00000480) Xc = 1/0.001809557 Xc = 552.6213302 Rounding to 3 significant figures gives 553 ohms.</span>
You might be interested in
La velocidad de un tren se reduce uniformemente de 12m/s a 5m/s. Sabiendo que durante ese tiempo recorre una distancia de 100 m.
MA_775_DIABLO [31]

Responder:

Explicación:

Dados los siguientes datos

Valor inicial u = 12 m / s

velocidad final v = 5 m / s

Distancia S = 100 m

Necesario

aceleración del tren.

Usando la ecuación de movimiento

v² = u² + 2as

2as = v²-u²

a = v²-u² / 2s

Sustituyendo los valores dados para obtener la aceleración que tenemos;

a = 5²-12² / 2 (100)

a = 25-144 / 200

a = -119/200

a = -0,595 m / s²

Por tanto, la aceleración del tren durante este período es de -0,595 m / s²

b) Si el tren viaja a una parada desde 5 m / s, su velocidad final será cero y su velocidad inicial u será 5 m / s

Para obtener la distancia durante este período, sustituiremos u = 5 m / s, v = 0 m / sy a = -1,19 m / s² en la ecuación de movimiento anterior;

v² = u² + 2as

0² = 5²-2 (0.595) s

0 = 25-1,19 s

1,19 s = 25

s = 25 / 1,19

Responder:

Explicación:

Dados los siguientes datos

Valor inicial u = 12 m / s

velocidad final v = 5 m / s

Distancia S = 100 m

Necesario

aceleración del tren.

Usando la ecuación de movimiento

v² = u² + 2as

2as = v²-u²

a = v²-u² / 2s

Sustituyendo los valores dados para obtener la aceleración que tenemos;

a = 5²-12² / 2 (100)

a = 25-144 / 200

a = -119/200

a = -0,595 m / s²

Por tanto, la aceleración del tren durante este período es de -0,595 m / s²

b) Si el tren viaja a una parada desde 5 m / s, su velocidad final será cero y su velocidad inicial u será 5 m / s

Para obtener la distancia durante este período, sustituiremos u = 5 m / s, v = 0 m / sy a = -1,19 m / s² en la ecuación de movimiento anterior;

v² = u² + 2as

0² = 5²-2 (0.595) s

0 = 25-1,19 s

1,19 s = 25

s = 25 / 1,19

s = 21,0 m

Por lo tanto, la distancia que recorre hasta detenerse asumiendo la misma aceleración es 21.0 m

6 0
3 years ago
Classify each of the following chemical reactions. Upper S plus upper O Subscript 2 right arrow upper S upper O subscript 2. Upp
vodka [1.7K]

Check attached image.

4 0
3 years ago
The 45-g arrow is launched so that it hits and embeds in a 1.40 kg block. The block hangs from strings. After the arrow joins th
worty [1.4K]

Question: How fast was the arrow moving before it joined the block?

Answer:

The arrow was moving at 15.9 m/s.

Explanation:

The law of conservation of energy says that the kinetic energy of the arrow must be converted into the potential energy of the block and arrow after it they join:

\dfrac{1}{2}m_av^2 = (m_b+m_a)\Delta Hg

where m_a is the mass of the arrow, m_b is the mass of the block, \Delta H of the change in height of the block after the collision, and v is the velocity of the arrow before it hit the block.

Solving for the velocity v, we get:

$v = \sqrt{\frac{2(m_b+m_a)\Delta Hg}{m_a} } $

and we put in the numerical values

m_a = 0.045kg,

m_b = 1.40kg,

\Delta H = 0.4m,

g= 9.8m/s^2

and simplify to get:

\boxed{ v= 15.9m/s}

The arrow was moving at 15.9 m/s

6 0
3 years ago
How did ALS impact Stephen Hawking?
olga nikolaevna [1]

Answer:

Professor Hawking had just turned 21 when he was diagnosed with a very rare slow-progressing form of ALS, a form of motor neurone disease (MND). He was at the end of his time at Oxford when he started to notice early signs of his disease. He was getting more clumsy and fell over several times without knowing why.

Explanation:

none

6 0
3 years ago
Multiply.<br> (2x + 4)(x - 4)
sergij07 [2.7K]

Answer:

(2x + 4)(x - 4)=2x^2-4x-16

7 0
3 years ago
Other questions:
  • Where does the autotroph get its energy from
    9·1 answer
  • Which of the following are likely to be affected by a magnet? Check all that apply.
    14·2 answers
  • A 50 kg box hangs from a rope. What is the tension in the rope if: The box is at rest? The box moves up at a steady 5.0 m/s? The
    11·1 answer
  • Help on 9 and 10! Please help me!
    10·1 answer
  • 30 POINTS!!
    14·1 answer
  • Expresa en terminos de la unidad fundamental
    6·1 answer
  • The two uniform, slender rods B1and B2, each of mass 2kg, are pinned together at P, and then B1is suspended from a pin at O. (Th
    5·1 answer
  • 02<br>The ano ture of a converges<br>து<br>The serie<br>atooaod<br>பி<br>5​
    6·1 answer
  • Please help me guys <br>a.<br>b.<br>c.​
    9·1 answer
  • A ball is gently dropped from a height of 20 m. If its velocity Increases uniformly at the rate of 10 m s2, with what velocity w
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!