Question

An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of the electric force on this electron due to this field

Answer 1

Answer:

$2.24 \times 10^{-14}$ Newtons

Explanation:

Magnitude of charge on the electron = q = $1.6 \times 10^{-19}$ Coulombs

The negative sign in the question statement indicates that the charge is negative.

Magnitude of Electric Field experienced by the electron = E = $1.4 \times 10^{5}$ Newtons/Coulomb

Magnitude of Force on the electron = F = ?

The relation between the charge, electric field and the force on the charge because of electric field is given by:

$E=\frac{F}{q}$

From here we can write:

F = qE

Using the values, we get:

$F = 1.6 \times 10^{-19} \times 1.4 \times 10^{5}\\\\ F = 2.24 \times 10^{-14}$

Thus, the magnitude of the electric force experience by the electron would be $2.24 \times 10^{-14}$ Newtons