2 years ago

!!!I NEED HELP ASAP!!!!

Mathematics

2 answers:

jolli1 [7]2 years ago

8 0

It would be the first option, I hope you have a great day

omeli [17]2 years ago

3 0

Answer:

It would be the first option.

f(x) = -2 |x| + 1

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I need YOUR help fast!

joja [24]

Answer:

(5, 4) is correct.

First comes x, which is horizontal on the graph

Then comes y, which is vertical.

6 0

2 years ago

Simplify. x^3 ÷ x^5

fomenos

Answer:

x^-2

Step-by-step explanation:

(x*x*x)/(x*x*x*x*x)

1/x*x

1/x^2

x^-2

3 0

3 years ago

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The graph of the equation 2x2 + xy + y2 = 4 is the tilted ellipse pictured below; i.e. the points (x,y) in the plane that satisf

mihalych1998 [28]

Answer:

The slope of tangent at point (1,-2) is $\frac{2}{3}$ .

Step-by-step explanation:

The given equation of ellipse is

$2x^2+xy+y^2=4$

Differentiate both sides with respect to x.

$\frac{d}{dx}(2x^2+xy+y^2)=\frac{d}{dx}(4)$

$\frac{d}{dx}(2x^2)\frac{d}{dx}(xy)+\frac{d}{dx}(y^2)=\frac{d}{dx}(4)$

$4x+x\frac{dy}{dx}+y+2y\frac{dy}{dx}=0$

$(4x+y)+(x+2y)\frac{dy}{dx}=0$

$\frac{dy}{dx}=-\frac{4x+y}{x+2y}$

Calculate the value of \frac{dy}{dx} at (1,-2).

$\frac{dy}{dx}_{(1,-2)}=-\frac{4(1)+(-2)}{(1)+2(-2)}$

$\frac{dy}{dx}_{(1,-2)}=-\frac{2}{-3}$

$\frac{dy}{dx}_{(1,-2)}=\frac{2}{3}$

Therefore the slope of tangent at point (1,-2) is $\frac{2}{3}$ .

3 0

3 years ago

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What is 4.510 in word form

Crazy boy [7]

<span>
four and fifty-one hundredths</span>

7 0

3 years ago

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PLEASE HELP!!!!!!

vlada-n [284]

Answer:

I believe D. B12

5 0

3 years ago

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