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masha68 [24]
3 years ago
9

!!!I NEED HELP ASAP!!!!

Mathematics
2 answers:
jolli1 [7]3 years ago
8 0
It would be the first option, I hope you have a great day
omeli [17]3 years ago
3 0

Answer:

It would be the first option.

f(x) = -2 |x| + 1

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Sketch the graph of the given data on the accompanying coordinate plane. a)choose ad state an appropriate scale so that all of t
vodomira [7]
Part A
A good scale for y to use would be 100, since it fits in all of the f(x)'s and the next value (243) is obviously not going to fit.
As for x, you can use 4 or 5. If you do 5, you're not going to get to it though, because f(x) will be 243.

Part B

When our input increases by 1, our output multiplies by 3.
Multiplying by 3 x times can be represented as 3^x.
We start at 1, so we'd want to have 1\times3^x. However, 1 times anything doesn't change its value, so we can leave it out because it is redundant.

As for making the graph, just label your y axis 0 to 100, and your x axis 0 to 5.
Then mark out (0, 1), (1, 3), (2, 9), (3, 27), and (4, 81).
Draw a curve that includes all of these. It should hit y=100 a little after x=4, since x=5 is all the way at y=243.
6 0
3 years ago
A dinner plate has a circumference of 113.04 cm. What is the area of the dinner plate? (Use 3.14 for pi)
Triss [41]

Answer:

D

Step-by-step explanation:

5 0
2 years ago
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What is the calculator display for 5/12
Dmitry_Shevchenko [17]

5/12 = 0.4166666...

That is what it says on the calculator.

8 0
4 years ago
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Simplify the expression by combining like
Dennis_Churaev [7]

Answer:

9x² + 5x

Step-by-step explanation:

4x² + 6x + 5x²-x

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2 years ago
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Hence, write as single<br> frachon in its lowest terms.<br> 2/y-1 - 4/y^2-1
sleet_krkn [62]

Answer:

\frac{2}{y+1}

Step-by-step explanation:

Factorise the denominator of the second fraction

y² - 1 = (y - 1)(y + 1) ← difference of squares

To obtain a common denominator

multiply numerator/ denominator of first fraction by (y + 1)

= \frac{2(y+1)}{(y-1)(y+1)} - \frac{4}{(y-1)(y+1)} ← subtract numerators leaving the common denominator

= \frac{2y+2-4}{(y-1)(y+1)}

= \frac{2y-2}{(y-1)(y+1)}

= \frac{2(y-1)}{(y-1)(y+1)} ← cancel common factor (y - 1) on numerator/denominator

= \frac{2}{y+1}

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