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2 years ago

PLS HELP ME ;;;-;;;

Mathematics

1 answer:

Mandarinka [93]2 years ago

5 0

Answer:

X=11

Step-by-step explanation:

9x+6= (3x+2)+(70)

Simplify: 6x+6=72

6x+6=72

6x=66

x=11

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Find the distance between the points (-3, 11) and (5, 5).<br><br> 10<br> 2<br> 2

yanalaym [24]

Use the distance formula to find the distance between two points.

$d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d= \sqrt{(-3-5)^2+(11-5)^2} \\ d - \sqrt{-8^2+6^2} \\ d=\sqrt{64+36} \\ d = \sqrt{100} \\\\ \boxed{d=10}$

4 0

3 years ago

Read 2 more answers

a random sample of 4 claims are selected from a lot of 12 that has 3 nonconforming units. using the hypergeometric distribution

Sloan [31]

Answer:

The probability that the sample will contain exactly 0 nonconforming units is P=0.25.

The probability that the sample will contain exactly 1 nonconforming units is P=0.51.

Step-by-step explanation:

We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.

We can write the probability mass function as:

$P(x=k)=\frac{\binom{K}{k}\binom{N-K}{n-k}}{\binom{N}{n}}$

where k is the number of non-conforming units on the sample of n=4.

We can calculate the probability of getting no non-conforming units (k=0) as:

$P(x=0)=\frac{\binom{3}{0}\binom{9}{4}}{\binom{12}{4}}=\frac{1*126}{495}=\frac{126}{495} = 0.25$

We can calculate the probability of getting one non-conforming units (k=1) as:

$P(x=1)=\frac{\binom{3}{1}\binom{9}{3}}{\binom{12}{4}}=\frac{3*84}{495}=\frac{252}{495} = 0.51$

5 0

2 years ago

How can I calculate the value of x

AnnyKZ [126]

Solve 180=10x+10 to find your answer (:

8 0

2 years ago

A bag contains yellow marbles and red marbles, 77 in total. The number of yellow marbles is 5 more than 3 times the number of re

bulgar [2K]

Answer:

Step-by-step explanation:

yellow marbles=5+ 3r(r is the number of red marbles)

red marbles=3r

3r+3r+5=77

6r=77-5

6r=72

r=72/6=12

yellow marbles = 5 + 3r

5+ 12 x 3

5+ 36

=41

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2 years ago

Please help with this its a little confusing

Molodets [167]

What about it? What is the question?

8 0

1 year ago