Question

Identify the zeros of the quadratic function! Please help

Answer 1

Answer:

-2.79, -4.21

Step-by-step explanation:

The function seen in the graph is 0.5 (x + 3.5)² - 1.

Hence,

$0.5(x+3.5)^{2} -1=0\\0.5(x+3.5)^{2} =1\\(x+3.5)^{2} = 0.5\\x+3.5 = \sqrt{0.5}\\or\\ x+3.5=-\sqrt{0.5}$

Finding the first answer,

$x+3.5=\sqrt{0.5} \\x=\sqrt{0.5}-3.5\\x=-2.79 (3sf)$

Finding the second answer,

$x+3.5=-\sqrt{0.5}\\x=-\sqrt{0.5} -3.5\\x=-4.21(3sf)$