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Serggg [28]
3 years ago
12

In pea plants the allele for round seeds (R) are dominant to the allele for wrinkled seeds (r). The allele for yellow seeds (Y)

is dominant to the allele for green seeds (y). A heterozygous yellow, round seed plant is crossed with a seed that is green and wrinkled.
RrYy x rryy

What are the gamete combinations for the heterozygous parent?
A. RY, rY, Ry, ry
B. rr, yy, YY
C. Ry, ry, yy
Biology
1 answer:
SashulF [63]3 years ago
7 0

Answer:

The correct answer is -  A. RY, rY, Ry, ry

Explanation:

Gametes are the sex cells or reproductive cells that are haploid in number. Gametes carry only one allele of each gene or chromosome in any organism. The male gamete called an egg or ovum whereas the male gamete called sperm or pollen.

In this case, the heterozygous plant has the genotype RrYy. In each of the gametes, there would one allele of each gene. The gametes get a dominant R and a dominant Y allele and a recessive r and a recessive y allele. Each produces 25% each of RY, Ry, rY, and ry.

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Answer:

by testcrossing with a homozygous recessive partner

Explanation:

<u>If a pet cockroach exists whose zygosity is unknown, this can be determined by a test cross. A test cross involves crossing an organisms whose zygosity is unknown with a partner that is homozygous recessive for the same trait.</u>

Let us assume that brown body is represented by the allele B, the dominant allele. The homozygous recessive version would be bb.

The genotype of a brown cockroach whose zygosity is not known can be denoted as B_, where '_' can be a 'B' or a 'b'.

When B_ is crossed with bb:

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In other word, if the unknown genotype is bb, then _b becomes bb and the phenotype will be a alternate color (non-brown) body. This means that 50% of the progeny will appear brown while the remaining 50% will be in the alternate color. (<em>attached</em>

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