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emmasim [6.3K]
3 years ago
15

If Lisa gets $31.42 an hour, what is the minimum number of hours does she need to work to get $3392 a month.

Mathematics
2 answers:
Leto [7]3 years ago
8 0

Answer:

108

Step-by-step explanation:

All you need to do is take 3392 divided by 31.42 and you'll get 107.9567...

Since Lisa needs AT LEAST 3392 a month, she would have to work 108 hours in order to meet that requirement.

Vaselesa [24]3 years ago
8 0
About 110 hours
110x31
3410
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4 years ago
What is the vertex of g(x) = 3x2 − 12x + 7?<br><br> (−6, −5) <br> (−2, −5)<br> (2, −5)<br> (6, −5)
34kurt

Answer:

(2, -5)

Step-by-step explanation:

Convert to vertex form:

3x^2 - 12x + 7

= 3(x^2 - 4x) + 7

Completing the square:

= 3[ (x - 2)^2 - 4)] + 7

= 3(x - 2)^2 - 12 + 7

= 3(x - 2)^2 - 5.

Comparing with the general form

a(x - b)^2 + c  we see that the vertex is (b, c)  =   (2, -5).

4 0
3 years ago
What is the fraction for 0.2
Olenka [21]
1/5  this is the closest answer i can think of

3 0
3 years ago
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How do you do something like this?<br><br> (8/10)^-2
Nostrana [21]
( 4 / 5 )^-2 = ( 5 / 4 )^2 = 25 / 16 ;
4 0
4 years ago
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

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  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
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