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Studentka2010 [4]
2 years ago
7

Algebra help needed. Overwhelmed with other papers. See attached

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0

Answer:

Step-by-step explanation:

whitch answer how do you want us to answer

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If JK and LM are congruent and parallel, then JKL and MLK are congruent.
viktelen [127]

Answer:

Given statement is TRUE.

Step-by-step explanation:

Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.

We know that corresponding angles formed by transversal line are congruent.

Hence ∠JKL = ∠ MLK ...(i)

Now consider triangles JKL and MLK

JK = LM  {Given}

∠JKL = ∠ MLK { Using (i) }

KL = KL  {common sides}

Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.

Hence given statement is TRUE.

3 0
3 years ago
Which equation represents a circle with a center at (-4, 9) and a diameter of 10 units?
blsea [12.9K]

Answer:

(x+4)^2 + (y-9)^2 = 25

Step-by-step explanation:

We can use the equation (x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

The center is at (-4,9) and the diameter is 10 which means the radius is 10/2 or 5

(x- -4)^2 + (y-9)^2 = 5^2

(x+4)^2 + (y-9)^2 = 25

3 0
2 years ago
Someone help me with this
Alex

Answer:

y=7.5x, y=9.25x, y=6x

Step-by-step explanation:

on the first table we have for 2 tikets $ 15 so the price for one ticket (also known as unit price) is 15/2= $ 7.5

the equation for the price of ticket must be

y= 7.5 x (where y is price you pay for x number of tikets)

on the second table you can pick that you have $37 for 4 tikets so unit price is 37/4= $9.25 per one ticket

y=9.25x

last table $12 for 2 tikets so for one ticket is 12/2=$6

y=6x

7 0
3 years ago
Read 2 more answers
Find the variance of this probability distribution. Round to two decimal places.​
attashe74 [19]

Answer:

Variance = 4.68

Step-by-step explanation:

The formula for the variance is:

\sigma^{2} =\frac{\Sigma(X- \mu)^{2}}{N} \\or \\ \sigma^{2} =\frac{\Sigma(X)^{2}}{N} -\mu^{2} \\

Where:

X: Values \\\mu: Mean \\N: Number\ of\ values

The mean can be calculated as each value multiplied by its probability

\mu = 0*0.4 + 1*0.3 + 2*0.1+3*0.15+ 4*0.05=1.15

\frac{\Sigma (X)^{2}}{N} =\frac{(0^{2}+1^{2}+2^{2}+3^{2}+4^{2})}{5} =6

Replacing the mean and the summatory of X:

\sigma^{2} = \frac{\Sigma(X)^{2}}{N} -\mu^{2} \\= 6 - 1.15^{2}\\= 4.6775

4 0
3 years ago
What is the slope of a line perpendicular to the line passing through (1, -3) and (-4, 7)?
andrezito [222]

Answer:

-2

Step-by-step explanation:

m=\frac{y2-y1}{x2-x1}

7 0
3 years ago
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