Answer:
1) m = h - w/8
Subtract h from both sides.
m - h = -w/8
Subtract m from both sides.
-h = -m - w/8
Divide all terms by -1.
h = m + w/8.
2) m = h - w/8
Get rid of the denominator 8 by multiplying 8/1 to all terms.
8m = 8h - w
Add w on both sides and subtract 8m from both sides.
w = 8h - 8m
3) w = x + y/z
Get rid of the denominator z by multiplying it to all terms.
wz = xz + y
Subtract xz from both sides of the equation.
wz - xz = y OR y = wz - xz
4) w = x + y/z
Subtract x from both sides.
w - x = y/z
Get rid of the denominator by multiplying it to all terms.
wz - xz = y
Now factor the expression wz - xz.
z(w - x) = y
Divide both sides by w - x.
z = y / w - x
This is read as z equals to y divided by w minus x.
5) The area of a triangle is A = 1/2bh
First, get rid of the denominator by multiplying both sides by 2.
2A = bh
To find b, divide both sides by h.
2A/h = b
6) P = kt/v
Multiply both sides by v.
Pv = kt
Divide both sides by t.
Pv/t = k OR k = Pv/t.
Step-by-step explanation:
12 action films are shown.
This is because if the ratio is 1:2, that means that exactly half of the total amount of movies are action. Thus, to evaluate this problem, you would find half of 24.
I need to answer two questions in order to ask a question. sorry that i’m stupid and have no idea how to do this
<u>Answer</u><u> </u><u>:</u><u>-</u>
9(3+√3) feet
<u>Step </u><u>by</u><u> step</u><u> explanation</u><u> </u><u>:</u><u>-</u>
A triangle is given to us. In which one angle is 30° and length of one side is 18ft ( hypontenuse) .So here we can use trignometric Ratios to find values of rest sides. Let's lable the figure as ∆ABC .
Now here the other angle will be = (90°-30°)=60° .
<u>In ∆ABC , </u>
=> sin 30 ° = AB / AC
=> 1/2 = AB / 18ft
=> AB = 18ft/2
=> AB = 9ft .
<u>Again</u><u> </u><u>In</u><u> </u><u>∆</u><u> </u><u>ABC</u><u> </u><u>,</u><u> </u>
=> cos 30° = BC / AC
=> √3/2 = BC / 18ft
=> BC = 18 * √3/2 ft
=> BC = 9√3 ft .
Hence the perimeter will be equal to the sum of all sides = ( 18 + 9 + 9√3 ) ft = 27 + 9√3 ft = 9(3+√3) ft .
<h3>
<u>Hence </u><u>the</u><u> </u><u>perim</u><u>eter</u><u> of</u><u> the</u><u> </u><u>triangular</u><u> </u><u>pathway</u><u> </u><u>shown</u><u> </u><u>is</u><u> </u><u>9</u><u> </u><u>(</u><u> </u><u>3</u><u> </u><u>+</u><u> </u><u>√</u><u>3</u><u> </u><u>)</u><u> </u><u>ft</u><u> </u><u>.</u></h3>