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Daniel [21]
3 years ago
7

A typical electromagnetic signal from a communications satellite might have an intensity of 0.600 pW/m2 at the surface of the Ea

rth. Your satellite dish collects the energy of the electromagnetic signal from the satellite; then your dish passes that energy to its central receiver, where the signal can be processed by a circuit. The area of a satellite dish can be calculated from pi (3.1416) times the radius squared. If your satellite dish has a radius of 0.28 m, and if it is receiving the signal described above, how much electromagnetic energy is reflected to the central receiver in 2.5 minutes
Physics
1 answer:
ladessa [460]3 years ago
6 0

Answer:

The answer is "22.05 pJ"

Explanation:

Using formula:

Energy=power\times time\\\\Power=Intensity \times area

Calculating Energy:

=0.147 \times 2.5 \times 60 \times 10^{-12}\\\\=22.05\ pJ

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Questions on the photo
White raven [17]

Answer:

Option C: Third Class

Explanation:

This is third class because the effort or the input force is in the middle between the fulcrum and the load.

8 0
3 years ago
Why empty tin-cans ocillating for a longer time​
Natalija [7]

Answer: When you speak into the can, your voice creates air vibrations that travel into the can, vibrate the bottom of the can, which in turn vibrates the string all the way over to the other can, in turn vibrating the other can's bottom, then the air again.

Explanation:

3 0
3 years ago
There is a small scratch on a disco record located 14.5 cm from the center. When played, the scratch makes the record skip 30 ti
LuckyWell [14K]

Answer:

The linear speed of scratch is 45.55 cm/dec

Explanation:

The scratch located from the center at radial distance = 14.5 cm.

Each minute the skip of scratch when disco record played  = 30 times

Since, the scratch on the disc start revolving when disc is played and in one minute the scratch revolve 30 times. Therefore, the revolution = 30 RPM

Below is the calculation of linear speed of the scratch.

Angular \ velocity, \ w \ = \frac{2 \pi  \times RPM}{60} \\

w  =  \frac{2 \pi  \times 30}{60} = \pi  \ rad/dec \\

Linear \ velocity = wr \\

r = radial \ distance \\

v = \pi \times 14.5 \\

v = 45.55 cm/dec

3 0
3 years ago
An eagle is flying horizontally at a speed of 2.60 m/s when the fish in her talons wiggles loose and falls into the lake 4.70 m
dimulka [17.4K]

Answer:

Explanation:

The fish will have horizontal velocity of 2.6 m/s which is also the velocity of eagle. Additionally , he will have vertical velocity due to fall under gravity .

v² = u² + 2 g H .

v² = 0  + 2 x 9.8 x 4.7 m

= 92.12

v = 9.6 m /s

The fish's final velocity will have two components

vertical component = 9.6 m/s downwards

Horizontal component = 2.6 m /s  .

Resultant velocity = √ ( 9.6² + 2.6² )

= √ ( 92.16 + 6.76 )

= 9.9 m /s

3 0
3 years ago
Read 2 more answers
(a) A 1.00-μF capacitor is connected to a 15.0-V battery. How much energy is stored in the capacitor? ________ μJ (b) Had the ca
gulaghasi [49]

Answer:

(a) E_{ c} = 112.5 \mu J

(b) E'_{ c} = 18 \mu J

Solution:

According to the question:

Capacitance, C = 1.00\mu F = 1.00\times 10^{- 6} F

Voltage of the battery, V_{b} = 15.0 V

(a)The Energy stored in the Capacitor is given by:

E_{c} = \frac{1}{2}CV_{b}^{2}

E_{c} = \frac{1}{2}\times 1.00\times 10^{- 6}\times 15.0^{2}

E_{ c} = 112.5 \mu J

(b) When the voltage of the battery is 6.00 V, the the energy stored in the capacitor is given by:

E'_{c} = \frac{1}{2}CV'_{b}^{2}

E'_{c} = \frac{1}{2}\times 1.00\times 10^{- 6}\times 6.0^{2}

E'_{ c} = 18 \mu J

6 0
4 years ago
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