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Lubov Fominskaja [6]
1 year ago
6

find the gravitational force this shell exerts on a 1.60 kg point mass placed at the distance 5.01 m from the center of the shel

l.
Physics
1 answer:
RideAnS [48]1 year ago
7 0

The gravitational force of the shell exerts is 4.25m x 10¯¹² N.

We need to know about gravitational force to solve this problem. The gravitational force is the force caused by two masses of objects. The magnitude of gravitational force can be determined as

F = G.m1.m2 / R²

where F is the gravitational force, G is the gravitational constant (6.674 × 10¯¹¹ Nm²/kg²), m1 and m2 are the mass of the object and R is the radius.

From the question above, we know that

m1 = 1.6 kg

m2 = m

R = 5.01 m

By substituting the following parameters, we get

F = G.m1.m2 / R²

F = 6.674 × 10¯¹¹  . 1.6 . m / 5.01²

F = 4.25m x 10¯¹² N

where m is the mass of the shell

For more on gravitational force at: brainly.com/question/19050897

#SPJ4

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Answer:

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A 50.0 kg piece of rock slides down the side of Mt. Etna. That part of the volcano slopes up at 30.0° (from the horizontal). If
vesna_86 [32]

Answer:

0.224

Explanation:

There are two forces acting on the rock along the direction parallel to the slope:

- The component of the weight parallel to the slope, down, given by

mg sin \theta

where

m = 50.0 kg is the mass of the rock

g=9.8 m/s^2 is the acceleration of gravity

\theta=30^{\circ} is the angle of the slope

- The force of friction, up along the slope, given by

F_f=\mu R

where

\mu is the coefficient of friction

R is the normal reaction

So the equation of the forces along the direction parallel to the slope is

mg sin \theta - \mu R = ma (1)

where

a=3.0 m/s^2 is the acceleration

The normal reaction R can be found by looking at the equation of the forces along the direction perpendicular to the slope: in fact, we have that R balances the component of the weight perpendicular to the slope, so

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu mg cos \theta = ma

And solving for \mu, we find the coefficient of friction:

\mu = \frac{g sin \theta -a}{g cos \theta}=\frac{(9.8)(sin 30)-3.0}{(9.8)(cos 30)}=0.224

7 0
4 years ago
Defind wave.then explain how vibrations,waves,and energy are related to sound
vagabundo [1.1K]
Waves are either transversal stereotypical pictures of waves or longitudinal it goes in rings waves are just different forms of vibration of any kind of energy
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3 years ago
Read 2 more answers
In proton beam therapy, a beam of high-energy protons is used to kill cancerous cells in a tumor. In one system, the beam, which
Thepotemich [5.8K]

The number of protons that strike the tumor each second is 1.75 \times 10^8 protons.

<u>Given the following data:</u>

  • Energy of proton = 2.8 \times 10^{-11} Joules.
  • Current = 84 nA to A = 84 \times 10^{-9} Ampere.
  • Energy of total dose = 3.4 \times 10^{-3} Joules.

<u>Scientific data:</u>

  • Charge of proton = 1.602 \times 10^{-19} C.

To determine the number of protons that strike the tumor each second:

<h3>How to determine the number of protons.</h3>

Mathematically, the quantity of charge per unit time is given by this formula:

Q =It=Ne\\\\N = \frac{Q}{e}

<u>Where:</u>

  • N is the number of protons.
  • t is the time measured in seconds.
  • I is the current.
  • e is the charge of protons.

Substituting the parameters into the formula, we have;

N=\frac{2.8 \times 10^{-11} }{1.602 \times 10^{-19}} \\\\N = 1.75 \times 10^{8}protons.

Read more on charges here: brainly.com/question/14372859

8 0
2 years ago
Ellie has two wire circuits, each connected to its own 6 V battery. One circuit has a resistance of 0.80 Ω. The other circuit ca
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The second circuit with 4.5 A current has more resistance.

Explanation:

potential difference= 6 V

resistance of first circuit=0.80 Ω

for second circuit, current= i=4.5 A

using Ohm's law V= i R

6=4.5 R

R=1.33 Ω

So the second circuit has a greater resistance.

6 0
3 years ago
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