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Nadusha1986 [10]
3 years ago
15

An eagle is flying horizontally at a speed of 2.60 m/s when the fish in her talons wiggles loose and falls into the lake 4.70 m

below. Calculate the velocity (in m/s) of the fish just before it hits the water. (Assume that the eagle is flying in the x direction and that the y direction is up.)
Physics
2 answers:
patriot [66]3 years ago
4 0

Answer:

The speed of fish at the time of hitting the surface is 9.95 m/s.

Explanation:

Horizontal speed, u = 2.6 m/s

height, h = 4.7 m

Let the vertical velocity at the time of hitting to water is v.

Use third equation of motion

v^2 = u^2 - 2 gh \\\\v^2 = 0 + 2 \times 9.8\times 4.7\\\\v = 9.6 m/s

The net velocity with which the fish strikes to the water is

v' = \sqrt{9.6^2 + 2.6^2 }\\\\v' = 9.95 m/s

dimulka [17.4K]3 years ago
3 0

Answer:

Explanation:

The fish will have horizontal velocity of 2.6 m/s which is also the velocity of eagle. Additionally , he will have vertical velocity due to fall under gravity .

v² = u² + 2 g H .

v² = 0  + 2 x 9.8 x 4.7 m

= 92.12

v = 9.6 m /s

The fish's final velocity will have two components

vertical component = 9.6 m/s downwards

Horizontal component = 2.6 m /s  .

Resultant velocity = √ ( 9.6² + 2.6² )

= √ ( 92.16 + 6.76 )

= 9.9 m /s

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Answer:

ELASTIC collision

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Explanation:

As the ball bounces to the same height, it can be stated that the impact with the floor is ELASTIC.

As the floor does not move the conservation of the moment

            po = pf

            -mv1 = m v2

- v1 = v2

So the speed with which it descends is equal to the speed with which it rises

Therefore the kinetic energy of the ball before and after the collision is the same

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3 years ago
What happens when a resultant electric field exist in conductor​
klio [65]

Answer:

When an electric field exists in a conductor a current will flow.

This implies a voltage difference between two points on the conductor.

Electrostatics pertains to static charge distributions.

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Why must the electric field be normal to the surface at every point of a charged conductor?
solong [7]
-- If the field were inclined to the surface, then it would have
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3 0
3 years ago
A particle moves along a straight line with equation of motion s = f(t), where s is measured in meters and t in seconds. Find th
Rashid [163]

Answer:

The velocity of the particle = -1.92 m/s

The speed of the particle = 5.72 m/s

Explanation:

Given equation of motion;

f(t) = 18 \ + \ \frac{48}{t} \ + \ 1

Velocity is defined as the change in displacement with time.

V = \frac{df(t)}{dt} = -\frac{48}{t^2} \\\\at \ t = 5 \ s\\\\V = -\frac{48}{5^2} = \frac{-48}{25} = - 1.92 \ m/s

The distance traveled by the particle in 5 s:

s = f(5) = 18 + \frac{48}{5} + 1\\\\s= 28.6 \ m

The speed of the particle when t = 5s

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6 0
3 years ago
The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the
PIT_PIT [208]

The drag force is directly proportional to the square of the velocity of motion of the object. So as the speed is doubled, the magnitude of drag force will get quadrupled.

<u>Explanation: </u>

Drag force is the opposing or resisting force acting on any object by the medium in which it is moving. So in this case, you are riding a bicycle, thus the medium can be considered as air.

The formula for calculating drag force is as below:

               \text {Drag force }=\frac{1}{2} \rho v^{2} C_{D} A

Here, ρ is the density of the air molecules, v is the velocity or speed of the bicycle, CD is the drag coefficient and A is the area of the bicycle.

In the above equation, only the term velocity will be a varying quantity with respect to time and other quantities will remain constant throughout the single situation of riding of bicycle.

So, the equation can be,

             \text { Drag force }=k v^{2}

Where ,  

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Now given the speed of bicycle increased from v to 2v, so the initial drag force will be

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Thus, if the speed of the bicycle is doubled, the drag force will get increased by four times.

4 0
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