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3 years ago

The Family Fine Arts Center charges $ 22 per adult and $ 14 per child under 12

Mathematics

1 answer:

valina [46]3 years ago

5 0

Answer:

197 adult tickets and 354 child tickets were sold for the event.

Step-by-step explanation:

Given that the Family Fine Arts Center charges $ 22 per adult and $ 14 per child under 12 years old for its performances, and on a recent weekend evening when 551 people paid admission, the total receipts were $ 9290, to determine how many who paid were children under 12 years old the following calculation must be performed:

22 - 14 = 8

551 x 14 = 7.714

9,290 - 7,714 = 1,576

1,576 / 8 = 197

551 - 197 = 354

197 x 22 + 354 x 14 = X

4.334 + 4.956 = X

Therefore, 197 adult tickets and 354 child tickets were sold for the event.

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Find both inequality 2c-7\>9 and 5d+7/<32

solong [7]

2c -7 >= 9

2c >= 16

c >= 8

5d + 7 <= 32

5d <= 25

d <= 5

normal arthematic except diving over -1 or flipping (taking inverse -1) flips the operator

3 0

3 years ago

PLEASE HELPPPPP. URGEENNTT!!! I DONT KNOW HOW TO SOLVE THIS

Oksi-84 [34.3K]

Answer:

A = 58.7 degrees

B = 66.9 degrees

C = 34.1 degrees

Step-by-step explanation:

For <A:

Tan A = $\frac{opposite}{adjacent}$

Tan A = $\frac{23}{14}$

Tan A = 1.6

A = $Tan^{-1} 1.6$

A = 58.7 degrees

For <B:

Sin B = $\frac{opposite}{hypotenuse}$

Sin B = $\frac{23}{25}$

Sin B = 0.92

B = $Sin^{-1} 0.92$

B = 66.9 degrees

For <C:

Sin C = $\frac{opposite}{hypotenuse}$

Sin C = $\frac{14}{25}$

Sin C = 0.56

C = $Sin^{-1}0.56$

C = 34.1 degrees

6 0

3 years ago

A store sells both cold and hot beverages. Cold beverages, c, cost $1.50, while hot beverages, h, cost $2.00. On Saturday, drink

ra1l [238]

Answer:

The number of hot beverages sold were 45 and the number of cold beverages sold were 180.

Step-by-step explanation:

Let the number of cold beverages sold be $c$

And the number of hot beverages sold be $h$

According to the question:

c=4 $\times$ h...

$$$ 1.5 $\times$ c + 2 $\times$ h = Sale of any day

Part1:

For Saturday.

The sale is of $$$ 360

then

$$$ 1.5 $\times$ c + $$$ 2 $\times$ h = $$$ 360

Part 2:

Following the method of substitution.

And plugging the values of c=4 $\times$ h...in equation where the sales of Saturday is given.

1.5 $\times$ c + 2 $\times$ h =360

1.5 $\times$ 4 $\times$ h + 2 $\times$ h =360

6 $\times$ h + 2 $\times$ h= 360

8 $\times$ h=360

Dividing both sides with 8.

h= $\frac{360}{8}$

h=45

Inserting h=45 in c=4 $\times$ h...

we have c=4 $\times$ 45 = 180

So the number of hot beverages sold were 45 and the number of cold beverages sold were 180.

6 0

3 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

3 years ago

Read 2 more answers

The expression [(-7) ³ - (-7³)] - [(-7) ² + 7²] results in

Reil [10]

[(-7)(-7)(-7) + (-7)(-7)(-7)] - [(-7)(-7) + (7)(7)]
(-343 + -343) - (49 + 49)
-686 - 98 = -784
The answer is a) -784 :)

4 0

3 years ago

Read 2 more answers