Answer:
the specific heat capacity of ethanol is 2.4608 J/g°C
The variation in the final temperature is due to the rate of heat lost. Calorimeters do not dissipate or absorb energy
Explanation:
the solution is in the attached Word file
The volume of the textbook calculated by the student written to 3 significant figures is 992cm³
- According to this question, a student calculates the volume of his textbook and arrived at an answer of 991.880 cm³.
- To round up this digit to 3 significant figures, which means that only 3 significant numbers should appear in the answer.
- To do this, the number after the third number is 8, which means we can round up the value of 1 to 2. Hence, the volume of the textbook calculated by the student is 992cm³ in 3 s.f.
Learn more at: brainly.com/question/16563962?referrer=searchResults
Water is called a universal solvent because of its ability to dissolve different types of substances.
The basic unit of life is cell and a large portion of living cell (60%) is made up of water, this is because cells need water to survive. Biochemical reactions are always ongoing in the living cells and water act as solvents under which these reactions occur. Because of the high solubility of water, it is able to dissolve various substances needed by the body, this makes it easy for the substance to participate in chemical reactions and to move from one point to another. Without water biochemical reactions will not be able to occur in cells and this will lead to the death of the cells.
Answer:
pH = 4.8
Explanation:
A buffer is formed by a weak acid (0.145 M HC₂H₃O₂) and its conjugate base (0.202 M C₂H₃O₂⁻ coming from 0.202 M KC₂H₃O₂). The pH of a buffer system can be calculated using Henderson-Hasselbalch's equation.
![pH = pKa + log\frac{[base]}{[acid]} \\pH = -log(1.8 \times 10^{-5} )+log(\frac{0.202M}{0.145M} )\\pH=4.8](https://tex.z-dn.net/?f=pH%20%3D%20pKa%20%2B%20log%5Cfrac%7B%5Bbase%5D%7D%7B%5Bacid%5D%7D%20%5C%5CpH%20%3D%20-log%281.8%20%5Ctimes%2010%5E%7B-5%7D%20%29%2Blog%28%5Cfrac%7B0.202M%7D%7B0.145M%7D%20%29%5C%5CpH%3D4.8)
