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Mariulka [41]
3 years ago
15

How many Ni atoms are in 3.6 mol of Ni

Chemistry
1 answer:
Sliva [168]3 years ago
6 0
I believe that the answer is 1.8^24 of Ni atoms in 3.6 mol of Ni.

Hope this helps. :)

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Question 7-Which of the following is not an acid-base neutralization reaction?
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Answer:- It is choice D. H_2SO_4+2NaCl\rightarrow 2HCl+Na_2SO_4

Explanations:- In general, a neutralization reaction is the reaction of an acid with base to form salt and water.

in first reaction the reaction is taking place between ammonia(a base) and hydrochloric acid(an acid) to form their salt(ammonium chloride). So, it is an acid-base neutralization reaction.

In second reaction, sodium hydroxide(a base) is reacting with acetic acid(an acid) to form their salt(sodium acetate) and water. So, it is an acid-base neutralization reaction.

In third reaction, Nitric acid is reacting with calcium hydroxide(a base) to form a salt(calcium nitrate) and water. So, it is an acid-base neutralization reaction.

In fourth reaction, sulfuruc acid is reacting a sodium chloride(a salt) to give a double replacement reaction. It is not an acid-base neutralization reaction as it's not taking place between an acid and base.

So, the correct choice is D. H_2SO_4+2NaCl\rightarrow 2HCl+Na_2SO_4

7 0
3 years ago
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Margarita [4]

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8 0
3 years ago
A cylinder and piston assembly (defined as the system) is warmed by an external flame. The contents of the cylinder expand, doin
melomori [17]

Answer:

ΔE = 73 J

Explanation:

By the first law of thermodynamics, the energy in the system must conserved:

ΔE = Q - W

Where ΔE is the internal energy, Q is the heat flow (positive if it's absorbed by the system, and negative if the system loses heat), and W is the work (positive if the system is expanding, and negative if the system is compressing).

So, Q = + 551 J, and W = + 478 J

ΔE = 551 - 478

ΔE = 73 J

3 0
3 years ago
Alcohols are polar molecules. true false
viktelen [127]
All alcohols are polar. True
7 0
3 years ago
Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi
bija089 [108]

<u>Answer:</u> The value of K_c for the net reaction is \frac{K_b}{K_w}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b

<u>Equation 2:</u>  H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}

The net equation follows:

B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=K_1\times K_2

We are given:  

K_1=K_b

K_2=\frac{1}{K_w}

Putting values in above equation, we get:

K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}

Hence, the value of K_c for the net reaction is \frac{K_b}{K_w}

7 0
3 years ago
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