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3 years ago

Evaluate the following expression: 62 - 7(8 + 6 – 3²) ANSWER STAT!!

Mathematics

1 answer:

Anna11 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

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Rewrite the fraction as a decimal -33/25

sergiy2304 [10]

To rewrite something as a decimal, simply divide the numerator and denominator.
-33 / 25 = -1.32
So -33/25 = -1.32

3 0

3 years ago

What is the median of the data?

marta [7]

To find the median of the data, you have to first numerical order the data from smallest to largest:

$19, 18, 12, 22, 15, 14, 16, 16, 14, 14, 21, 18$
$12, 14, 14, 14, 15, 16, 16, 18, 18, 19, 21, 22$

Then, use your fingers and find the center number.

$16$ , <em />so the answer is C.

8 0

3 years ago

If α and β are the zeroes of the polynomial 6y 2 − 7y + 2, find a quadratic polynomial whose zeroes are 1 α and 1 β .

ollegr [7]

Answer:

$2y^2-7y+6=0$

Step-by-step explanation:

We are given that $\alpha$ and $\beta$ are the zeroes of the polynomial $6y^2-7y+2$

$y^2-\frac{7}{6}y+\frac{1}{3}$

We have to find a quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ .

General quadratic equation

$x^2-(sum\;of\;zeroes)x+ product\;of\;zeroes$

We get

$\alpha+\beta=\frac{7}{6}$

$\alpha \beta=\frac{1}{3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha \beta}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7/6}{1/3}$

$\frac{1}{\alpha}+\frac{1}{\beta}=\frac{7}{6}\times 3=7/2$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{\alpha \beta}$

$\frac{1}{\alpha}\times \frac{1}{\beta}=\frac{1}{1/3}=3$

Substitute the values

$y^2-(7/2)y+3=0$

$2y^2-7y+6=0$

Hence, the quadratic polynomial whose zeroes are $1/\alpha$ and $1/\beta$ is given by

$2y^2-7y+6=0$

4 0

3 years ago

The parent function f(x) = x2 is translated such that the function g(x) = –x2 + 6x – 5 represents the new function. What is true

kkurt [141]

Answer:

1. Translation 3 units to the right;

2. Reflection across the x-axis;

3. Translation 4 units up.

Step-by-step explanation:

First, rewrite the function $g(x)$ in following way:

$g(x)=-x^2+6x-5=-(x^2-6x)-5=-(x^2-6x+9-9)-5=-(x-3)^2+9-5=-(x-3)^2+4.$

Apply such transformations:

1. Translate the graph of the parent function $f(x)$ 3 units to the right to get the graph of the function $f_1(x)=(x-3)^2.$

2. Reflect the graph of the function $f_1(x)$ across the x-axis to get the graph of the function $f_2(x)=-(x-3)^2.$

3. Translate the graph of the function $f_2(x)$ 4 units up to get the graph of the function $g(x)=-(x-3)^2+4.$

8 0

4 years ago

Read 2 more answers

The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equatio

bixtya [17]

The correct option is (b) h=0.5cos( $\pi$ /6t)+9.5.

The equations can be used to model the height as a function of time, t, in hours is h=0.5cos( $\pi$ /6t)+9.5.

<h3>Equation of cosine function:</h3>

The following is a presentation of the cosine function's generic form;

y = a + cos(bx - c) + d

amplitude = a

b = cycle speed

Calculation for the model height;

The height, h (feet) of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet.

Obtain amplitude 'a' as

$\begin{aligned}a &=\frac{\text { Maximum value }-\text { Minimum value }}{2} \\a &=\frac{10-9}{2} \\a &=\frac{1}{2} \\a &=0.5\end{aligned}$

The time 'T' is calculated as-

$\begin{aligned}&\mathrm{T}=\frac{2 \pi}{\mathrm{b}} \\&12=\frac{2 \pi}{\mathrm{b}} \\&\mathrm{b}=\frac{2 \pi}{12} \\&\mathrm{~b}=\frac{\pi}{6}\end{aligned}$

Now, calculate 'd'

$\begin{aligned}&\mathrm{d}=\frac{\text { Maximum value }+\text { Minimum value }}{2} \\&\mathrm{~d}=\frac{10+9}{2} \\&\mathrm{~d}=\frac{19}{2} \\&\mathrm{~d}=9.5\end{aligned}$

Therefore, with the height as a function of time, t, expressed in hours, can be modeled by the following equations:

h=0.5cos( $\pi$ /6t)+9.5

To know more about the general equation of a cosine function, here

brainly.com/question/27587720

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The complete question is-

The height, h, in feet of the tip of the hour hand of a wall clock varies from 9 feet to 10 feet. Which of the following equations can be used to model the height as a function of time, t, in hours? Assume that the time at t = 0 is 12:00 a.m.

A. h=0.5cos( $\pi$ /12t)+9.5

B. h=0.5cos( $\pi$ /6t)+9.5

C. h=cos( $\pi$ /12t)+9

D. h=cos( $\pi$ /6t)+9

7 0

2 years ago