3 years ago

Help please.

Mathematics

1 answer:

lyudmila [28]3 years ago

6 0

Answer:

Step-by-step explanation:stupid

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√3=1.732 find the value of√75+1/2√48-√198

Nookie1986 [14]

Answer:

12.124-3 $\sqrt{22}$

Step-by-step explanation:

$\sqrt{75} = \sqrt{5^{2}*3} \\$

$\sqrt{48}= \sqrt{2^{2}*2^{2}*3} \\$

$\sqrt{198} =\sqrt{3^{2}*2*11} \\$

$\sqrt{75} +\frac{1}{2} *\sqrt{48} - \sqrt{198} \\\\\sqrt{5^{2}*3} +\frac{1}{2} *\sqrt{2^{2}*2^{2}*3} - \sqrt{3^{2}*2*11} \\\\5\sqrt{3} +\frac{1}{2} *4 \sqrt{3} - 3 \sqrt{2*11} \\\\5\sqrt{3} +2 \sqrt{3} - 3 \sqrt{22} \\\\5*1.732 +2*1.732 - 3 \sqrt{22} \\\\8.66 + 3.464 - 3 \sqrt{22}\\\\12.124- 3 \sqrt{22}$

4 0

3 years ago

Line l is a perpendicular bisector of line segment A C. It intersects line segment A C at point B. Line l also contains points D

N76 [4]

Answer:

First one is DC

Second one is AB.

Step-by-step explanation:

Just did them on edge.

3 0

3 years ago

Read 3 more answers

Please help me with this problem..

charle [14.2K]

Answer:

y = 6

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 3 when x = 9, then

k = $\frac{y}{x}$ = $\frac{3}{9}$ = $\frac{1}{3}$ , thus

y = $\frac{1}{3}$ x ← equation of variation

When x = 18, then

y = $\frac{1}{3}$ × 18 = $\frac{18}{3}$ = 6

5 0

3 years ago

Exercise 1.2 1 Round each of these numbers to the degree of accuracy shown in brackets. a) 7765 (nearest hundred). b) 1099 (near

wlad13 [49]

Answer:

a. 700

b. 1000

c. 80

d. 700

6 0

2 years ago

If a line perpendicular to 2y=x+5 that passes through (2,1) using the slope- intercept form

arlik [135]

Slope of 2y = x + 5:-
This is y = 0.5 x + 2.5 in slope intercept form so its slope = 0.5

Slope of the line perpendicular to it = -1 / 0.5 = -2

it passes through (2 , 1) so we have

y- 1 = -2(x - 2)
y = -2x + 4 + 1

The answer is y = -2x + 5

4 0

3 years ago