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nasty-shy [4]
3 years ago
13

What is the lead coefficient in the product of ( -2x -3)(4x + 5) *

Mathematics
1 answer:
Murljashka [212]3 years ago
4 0

Answer:

Step-by-step explanation:

(-2x-3)(4x+5) = -(2x+3)(4x+5) = -(8x^2+12x+10x+15) = -8x^2 - 22x - 15

Leading coefficient is -8

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Rectangle PQRS is rotated 90 counterclockwise about the origin what are the coordinates of point Q
inna [77]
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.

When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)

Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)

point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)

point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)

Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)

Hope this helps :)
5 0
3 years ago
Read 2 more answers
clark made a model of his house. his house is 30 1/2 feet long. the dimensions of the model were 1/25 the dimensions of clarks a
balandron [24]

Answer:

1.22 feet, or 1  11/50 ft

Step-by-step explanation:

Find 1/25 th of 30 1/2 feet:

 1        61 ft

----- * ---------- = 1.22 feet, or 1  11/50 ft

25      2

The length of the model is  1.22 feet, or 1  11/50 ft

7 0
4 years ago
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
Point A is located at (-2, -6) and is translated 4 units up. What are the coordinates of point A'?
defon

Answer:

(-2, -2)

Step-by-step explanation:

Red point represents (-2,-6) while blue point represents (-2,-2). count the numbers upward and it'll be 4 units. Best thing to do in this problem is to plot the given points and go from there.

4 0
3 years ago
Read 2 more answers
Solve y = log3243. anything helps!
9966 [12]
Y=3.51
You could just plug it into your calculator!
3 0
3 years ago
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