4 was rolled 2 times
5 also 2 times
6 was rolled 4 times
So the result was greater than three eight times out of 12 rolls.
P=8/12=2/3
Given the two functions:
![\begin{gathered} R(x)=2\sqrt[]{x} \\ S(x)=\sqrt[]{x} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20R%28x%29%3D2%5Csqrt%5B%5D%7Bx%7D%20%5C%5C%20S%28x%29%3D%5Csqrt%5B%5D%7Bx%7D%20%5Cend%7Bgathered%7D)
We need to find (RoS)(4). THis is the functional composition. We take S(x) and put it into R(x) and then put "4" into that composed function. Shown below is the process:
![(RoS)(x)=2\sqrt[]{\sqrt[]{x}}](https://tex.z-dn.net/?f=%28RoS%29%28x%29%3D2%5Csqrt%5B%5D%7B%5Csqrt%5B%5D%7Bx%7D%7D)
When we plug in "4", into "x", we have:
Answer: $7142.86
Step-by-step explanation:
Let the amount to be invested in the bond be represented by y.
Based on this, the amount to be invested in the CD will be: = 50000 - y.
From the information given, yearly interest on bond is 12%, this will be:
= 12% × y = 0.12 × y = 0.12y
Also, interest on CD will be:
= 5% × (50000 - y)
= 0.05(50000 - y)
Then, the equation to get the amount to be invested in bond will be:
0.12y + 0.05(50000 - y) = 3000
0.12y + 2500 - 0.05y = 3000
0.12y - 0.05y = 3000 - 2500
0.07y = 500
y = 500/0.07
y = 7142.8571
y = 7142.86
The amount to be invested in bond will be $7142.86
The surface area is 33ft square.
Answer:
20
Step-by-step explanation:
12 = 6/10 x
120 = 6x
x = 20