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navik [9.2K]
3 years ago
7

What is the area of a rectangle with side lengths 2/5 feet and 4/6 feet?

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

\frac{4}{15}  (4/15)

Step-by-step explanation:

\frac{4}{6}=\frac{2}{3}

\frac{2}{5}*\frac{2}{3};

1- Multiply the numerators:

2*2=4

2- Multiply the denominators:

5*3=15

3- Thus:

\frac{2}{5}*\frac{2}{3}= \frac{4}{15}

Hope this helps ;)

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What is the value of x?​
vladimir1956 [14]

Answer:

Step-by-step explanation:

x + 112 + 133+128+100+120= 720

x + 593 = 720

x = 127

3 0
3 years ago
18g + 24 write the expression in two other ways.
TiliK225 [7]
1) 6(3g+4)

2) 2(9g+12)
4 0
2 years ago
Solve these linear equations by Cramer's Rules Xj=det Bj / det A:
timurjin [86]

Answer:

(a)x_1=-2,x_2=1

(b)x_1=\frac{3}{4} ,x_2=-\frac{1}{2} ,x_3=\frac{1}{4}

Step-by-step explanation:

(a) For using Cramer's rule you need to find matrix A and the matrix B_j for each variable. The matrix A is formed with the coefficients of the variables in the system. The first step is to accommodate the equations, one under the other, to get A more easily.

2x_1+5x_2=1\\x_1+4x_2=2

\therefore A=\left[\begin{array}{cc}2&5\\1&4\end{array}\right]

To get B_1, replace in the matrix A the 1st column with the results of the equations:

B_1=\left[\begin{array}{cc}1&5\\2&4\end{array}\right]

To get B_2, replace in the matrix A the 2nd column with the results of the equations:

B_2=\left[\begin{array}{cc}2&1\\1&2\end{array}\right]

Apply the rule to solve x_1:

x_1=\frac{det\left(\begin{array}{cc}1&5\\2&4\end{array}\right)}{det\left(\begin{array}{cc}2&5\\1&4\end{array}\right)} =\frac{(1)(4)-(2)(5)}{(2)(4)-(1)(5)} =\frac{4-10}{8-5}=\frac{-6}{3}=-2\\x_1=-2

In the case of B2,  the determinant is going to be zero. Instead of using the rule, substitute the values ​​of the variable x_1 in one of the equations and solve for x_2:

2x_1+5x_2=1\\2(-2)+5x_2=1\\-4+5x_2=1\\5x_2=1+4\\ 5x_2=5\\x_2=1

(b) In this system, follow the same steps,ust remember B_3 is formed by replacing the 3rd column of A with the results of the equations:

2x_1+x_2 =1\\x_1+2x_2+x_3=0\\x_2+2x_3=0

\therefore A=\left[\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right]

B_1=\left[\begin{array}{ccc}1&1&0\\0&2&1\\0&1&2\end{array}\right]

B_2=\left[\begin{array}{ccc}2&1&0\\1&0&1\\0&0&2\end{array}\right]

B_3=\left[\begin{array}{ccc}2&1&1\\1&2&0\\0&1&0\end{array}\right]

x_1=\frac{det\left(\begin{array}{ccc}1&1&0\\0&2&1\\0&1&2\end{array}\right)}{det\left(\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right)} =\frac{1(2)(2)+(0)(1)(0)+(0)(1)(1)-(1)(1)(1)-(0)(1)(2)-(0)(2)(0)}{(2)(2)(2)+(1)(1)(0)+(0)(1)(1)-(2)(1)(1)-(1)(1)(2)-(0)(2)(0)}\\ x_1=\frac{4+0+0-1-0-0}{8+0+0-2-2-0} =\frac{3}{4} \\x_1=\frac{3}{4}

x_2=\frac{det\left(\begin{array}{ccc}2&1&0\\1&0&1\\0&0&2\end{array}\right)}{det\left(\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right)} =\frac{(2)(0)(2)+(1)(0)(0)+(0)(1)(1)-(2)(0)(1)-(1)(1)(2)-(0)(0)(0)}{4} \\x_2=\frac{0+0+0-0-2-0}{4}=\frac{-2}{4}=-\frac{1}{2}\\x_2=-\frac{1}{2}

x_3=\frac{det\left(\begin{array}{ccc}2&1&1\\1&2&0\\0&1&0\end{array}\right)}{det\left(\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right)}=\frac{(2)(2)(0)+(1)(1)(1)+(0)(1)(0)-(2)(1)(0)-(1)(1)(0)-(0)(2)(1)}{4} \\x_3=\frac{0+1+0-0-0-0}{4}=\frac{1}{4}\\x_3=\frac{1}{4}

6 0
3 years ago
Please help I need help
qaws [65]

The first answer of part A is 32

So 4y means you have to multiply 4 by y, which is 20 since 4x5=20

And then you add 12, which is 32.

The second answer to part A is 40

With the second question of part a, the expression is basically saying 4 times whatever 5+3 is. So 5+3= 8, and 4(8) is 40

For part B, they are equivalent because let’s pretend y=2. 12+4y= 20. And then 4(y+3) would equal 20 because 4(2)=8 and 4(3)=12 and 8+12=20. This might not be the answer that your teacher is looking for, but it’s still a right answer so technically they can’t say it’s wrong unless you have a super unfair teacher

3 0
2 years ago
Is this a parallelogram and why?
oksano4ka [1.4K]

the rectangle is but the line is not because the line has to have another side !

3 0
2 years ago
Read 2 more answers
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