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serg [7]
3 years ago
10

Solve the equation. 4^2x – 5 = 64

Mathematics
2 answers:
KiRa [710]3 years ago
7 0
X= 4.3125 or x= 4.313
jok3333 [9.3K]3 years ago
5 0
The x would be \sqrt{69} all over 2
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Raise the sum of b and a to the 10th power the topic is writing an expression. PLEASE HELP !
otez555 [7]

Answer:

(b + a)^{10}

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3 years ago
What us the answer to x + 6 = - 10
Vlad [161]

Answer:

-16

Step-by-step explanation:

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2 years ago
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Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

3 0
3 years ago
The given angle is in standard position. Determine the quadrant in which the angle lies. -25°
Veronika [31]
The terminal end of the angle has dropped 25° under the x-axis.
That's Quadrant-IV .
6 0
3 years ago
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A triangle with sides lengths 7, 9 and 11 is a right triangle. true or false
d1i1m1o1n [39]

You can check whether this is true using Pythagoras' Theorem. The Pythagorean Theorem:

a² + b² = c², where c is the hypotenuse of a right triangle.

Let's plug in the given values and check the validity of the statement.

a² + b² = c²

7² + 9² = 11²

49 + 81 = 121

130 = 121

This is false. Thus,

Answer:

False - a triangle with side lengths 7, 9, and 11 is not a right triangle.

3 0
3 years ago
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