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suter [353]
3 years ago
12

Question in image Show ur work

Mathematics
2 answers:
Soloha48 [4]3 years ago
4 0
−
3.1
x
+
7
−
7.4
=
1.5
x
−
6
(
x
−
3
2
)
Step 1: Simplify both sides of the equation.
−
3.1
x
+
7
−
7.4
=
1.5
x
−
6
(
x
−
3
2
)
−
3.1
x
+
7
+
−
7.4
=
1.5
x
+
(
−
6
)
(
x
)
+
(
−
6
)
(
−
3
2
)
(Distribute)
−
3.1
x
+
7
+
−
7.4
=
1.5
x
+
−
6
x
+
9
(
−
3.1
x
)
+
(
7
+
−
7.4
)
=
(
1.5
x
+
−
6
x
)
+
(
9
)
(Combine Like Terms)
−
3.1
x
+
−
0.4
=
−
4.5
x
+
9
−
3.1
x
−
0.4
=
−
4.5
x
+
9
Step 2: Add 4.5x to both sides.
−
3.1
x
−
0.4
+
4.5
x
=
−
4.5
x
+
9
+
4.5
x
1.4
x
−
0.4
=
9
Step 3: Add 0.4 to both sides.
1.4
x
−
0.4
+
0.4
=
9
+
0.4
1.4
x
=
9.4
Step 4: Divide both sides by 1.4.
1.4
x
1.4
=
9.4
1.4
x
=
6.714286
GaryK [48]3 years ago
3 0

Answer:

x= -1/3

Step-by-step explanation:

In the picture attached. if still doubting the answer, check by Substituing the value of x in the equation given.

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Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being
Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \sigma = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, H_A : \sigma < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, <u><em>the test statistics</em></u>  =  \frac{(25-1)\times 0.047^{2} }{0.065^{2} }  ~  \chi^{2}__2_4   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0
3 years ago
If (2 +3i)^2 + (2 - 3i)^2 = a + bia =b=
Shalnov [3]

(2 + 3i)^2 = 4 + 12i + 9(-1)

= 4 + 12i - 9

= -5 + 12i

(2 - 3i)^2 = 4 - 12i - 9(-1)

= 4 - 12i + 9

= 13 - 12i

REsult

= -5 + 12i + 13 - 12i

= 8 - 0i

Then

a = 8 and b = 0

7 0
2 years ago
A shop owner offered a 20% discount off the regular price of a mirror, The amount of the
AVprozaik [17]
A=15
I guessed and checked $15 - 20% and got 3
6 0
3 years ago
I dont understand how to do this​
krok68 [10]
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5 0
3 years ago
a telephone pole casts a 10 food shadow. A horse that stands 5.5 feet tall casts a 2.5 foot shadow. How tall is the pole?
Fittoniya [83]

Answer:

72

i think i remember doing this

8 0
3 years ago
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