All categories

3 years ago

What is the product of 68 and 90?

Mathematics

2 answers:

pantera1 [17]3 years ago

8 0

The product is the result of multiplying.

68 x 90 = 6,120

So, the product of 68 and 90 is 6,120.

Hope this helps. :)

Taya2010 [7]3 years ago

5 0

The product of 68 and 90 is 540. I got 540 because when you start at the ones place you multiply 8 times 0 which gives you 0. Finally, you go to the tens place and multiply 6 times whivh gives you 54. So, this is how I got 540.

I hope this helps!!!!!!!!!!!!!!!

You might be interested in

Jeremy swims for 5 3/5 kilometers in a 7 Day period. she swims the same distance each day. what distance does he swim in each da

disa [49]

Answer:

Step-by-step explanation:

You turn 5 3/5 into an improper fraction, to do that you do 5 x 5 = 25 then 25 + 3 = 28/5

so in a 7 day period she swims 5.6 kilometers. So you have to do 5.6/7 = 0.8

So it would be 0.8 kilometers in a day which is 4/5 kilometers so I don't know if the answers were just wrong?

5 0

3 years ago

Anyone want to help me out on this question?

kvasek [131]

Answer:

i think it’s 2/7

5 0

3 years ago

What is the value of X ??

DochEvi [55]

The value of X would be _#_##_#_#_#_#_##_#_#_#

8 0

3 years ago

Which equations will help you solve this problem? There are 35 water balloons in a bucket. If they are split equally among 5 chi

ser-zykov [4K]

The last one.

Hopes this helps! (:

6 0

2 years ago

Read 2 more answers

Suppose a lawn and garden company wants to determine the current percentage of customers who use fertilizer on their lawns. How

marishachu [46]

Answer:

n=601

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have a prior estimation for the proportion we can use 0.5 as estimation. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.96})^2}=600.25$

And rounded up we have that n=601

3 0

3 years ago