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3 years ago

8

An object in space is initially stationary relative to the Earth. Then, a force begins acting on the object, starting with a for

ce of 0 N, and increasing at a uniform rate until the magnitude of the force is 36 N after the force has acted for 35 s. The body has a mass of 10 kg. What is the speed of the object at 35 s?1. 4.4 m/s2. 8.8 m/s3. 11458.3 m/s4. 2750 m/s5. Insufficient information to answer6. 22916.7 m/s7. 110 m/s8. 5500 m/s9. 220 m/s

1 answer:

11111nata11111 [884]3 years ago

8 0

Answer:

v_f =63 m/s

Explanation:

given,

starting force = 0 N

uniform rate increase to 36 N

time of action of Force = 35 s

mass of the body = 10 Kg

Speed of the object = ?

From the given data

if we plot F-t curve we will get a triangular shape

we know,

Impulse = Area between F-t curve

= (1/2) x base x height

= 0.5 x 35 x 36

= 630 N.s

now use Impulse-momentum theorem

Impulse = change in momentum

630 = 10 x (v_f - vi)

630 = 10 x (v_f - 0)

v_f =63 m/s

Speed of the object at 35 sec is equal to v_f =63 m/s

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