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xxTIMURxx [149]
3 years ago
5

What is the nearest whole percent of 40

Mathematics
2 answers:
vova2212 [387]3 years ago
8 0
I think it’s 40 i’m not sure tho
Alexeev081 [22]3 years ago
8 0
Percent equal : 40%
Decimal equal : 0.4
Fraction equal : 2/5
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What is 50%+100094648%
nataly862011 [7]

Answer:

Percent : 10,009,514‬

Decimal : 1000946.98

Step-by-step explanation:

7 0
3 years ago
Help ASSAP . Find the perimeter I will give you 20 points and brainlyist.
Tpy6a [65]

Answer:

I think it may be 120 cm

Step-by-step explanation:

A F is 13 using pythagorean theorem on triangle CED and applying the hypotenuse length to A F.

ABC is similar to triangle CED and is dilated by a factor of 3  so the base is 36.

using pythagorean theorem on triangle ABC gets the hypotenuse length of 39 which can be applied to FE

add all the values together

39 + 13 + 15 + 36 +12 +5 = 120

5 0
3 years ago
Angle 1 is 50 degrees. Which angle is also 50 degrees?
solong [7]

Answer:

Step-by-step explanation:

angle 1= 50 degrees

x angle=50 degrees

cross multiply and you get and you get <u><em>1</em></u> as your answer

4 0
3 years ago
The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27
Naddik [55]
ANSWER
3\pi sq.\: in.

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

R:r=3:1

We can rewrite it as fractions to get,

\frac{R}{r} = \frac{3}{1}

We make R the subject to get,

R = 3r

The area of the bigger circle can be found using the formula,

Area=\pi {r}^{2}

This implies that,

Area=\pi ({3r})^{2}

Area=9\pi {r}^{2}

But it was given in the question that, the area of the bigger circle is 27π.

27\pi=9\pi {r}^{2}

We divide through by 9π to get,

3 = {r}^{2}

This means that,
r = \sqrt{3}

The area of the smaller circle is therefore

= \pi {( \sqrt{3}) }^{2}

= 3\pi
8 0
3 years ago
Read 2 more answers
Alex purchased a new car for $28000. The car depreciates 7.25% each year. what will the price be in 5 years?
dalvyx [7]
Use the depreciation formula.

\sf p(1-r)^n

Where 'p' is the principal value, 'r' is the rate it depreciates, and 'n' is the time. Just plug in what we know:

\sf 28000(1-0.0725)^5

Simplify by subtracting:

\sf 28000(0.9275)^5

Simplify the exponent:

\sf 28000(0.6864)

Multiply:

\sf\approx\boxed{\sf\$ 19219.20}
8 0
3 years ago
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