Let’s assume the following given:
Speed = 129 m/s
Time = 2,900,000 s
Find:
Distance = ?
Solution:
In order to get the distance, we multiply speed and time.
Distance = Speed * Time
Distance = 129 m/s * 2,900,000 s
Distance = 374,100,000 m
Next, we will convert the distance from meters to kilometers
by dividing the distance with 1,000 m.
374,100,000 m / 1,000 m = 374,100 km
<span>The last step would be converting the travelled distance in
kilometers to the nearest ten thousand.
Therefore, the travelled distance in kilometers to the nearest ten thousand is
370,000 km.</span>
Answer:
m = 3/2
Step-by-step explanation:
You want to find the slope, or the change in y coordinates over change in x-coordinates.
The first given point is E(-2, -4)
The second point is F(2, 2)
Coordinates are given in (x, y), so following the equation and computing the x and y coordinates of E - F for both the numerator and denominator:
![\frac{y_2 - y_1}{x_2-x_1} = \frac{-4 -2}{-2 -2} = \frac{-6}{-4} = \frac{3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7By_2%20-%20y_1%7D%7Bx_2-x_1%7D%20%20%3D%20%20%5Cfrac%7B-4%20-2%7D%7B-2%20-2%7D%20%3D%20%5Cfrac%7B-6%7D%7B-4%7D%20%3D%20%5Cfrac%7B3%7D%7B2%7D)
You could also have went the other way and calculated F - E for the numerator and denominator and get the same answer.
Finally, to check you can also look at the graph through the rise over run (rise/run) method and see that from E, you go up 3 (rise) and to the right 2 (run) to get to the next point on the line.
15-6= 9 9+7=16
It should be written as 6+7-15
The y value of I is (5(2) + 3(5))/(3 + 5) = (10 + 15)/8 = 25/8 = 3.125