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2 years ago

Which expression has a negative value?

Mathematics

2 answers:

user100 [1]2 years ago

7 0

It would be 35? is this right

Tom [10]2 years ago

5 0

Negative 35 divided by 5

Step-by-step explanation:Have a good day :)

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Someone please answer !!!!

Goryan [66]

The answer is C

By the way, that expression means "n choose k". Hope I helped!

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2 years ago

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What is the area of the given circle in terms of pi

ser-zykov [4K]

3.14(3.3)(3.3)
3.13(10.89)

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2 years ago

2 numbers are such that if 7 is added to the first number, a number twice the second number is obtained. If 20 is added to the s

Eduardwww [97]

Answer:

1st= 47/7 or 6.71

2nd= 48/7 or 6.857

Step-by-step explanation:

1st number =X and 2nd number = Y

According to question, X+7=2Y

20+Y=4X

X=2Y-7 (from 1st condition)

putting in it second

20+Y=4(2Y-7)

20+Y=8Y-28

20+28=8Y-Y

48=7Y

Y=48/7

so X=2(48/7)-7

=96-49/7

47/7

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3 years ago

Consider the following scenario describing Mr. Smith's math students: A list pairs math grades with student heights.

KonstantinChe [14]

Answer:

No, Because students who have the same math grade can be different heights

Step-by-step explanation:

C is the answer DO NOT PICK D

You have the put the correct input and output IN ORDER so D is the wrong answer

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2 years ago

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<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago